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Sliva [168]
3 years ago
15

a helium balloon has a volume of 2.95 liters at 25 c. the volume of the ballon decreased to 2.25 l after it is placed outside on

a cold day. what is the outside temperature in c?
Chemistry
1 answer:
OleMash [197]3 years ago
3 0

Answer:

The outside temperature is -45.8°C

Explanation:

When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).

V1 / T1 = V2 / T2

2.95L/298K = 2.25L / T2

(2.95L/298K ) . T2 = 2.25L

T2 = 2.25L . 298K / 2.95L

T2 = 227.2K

T°K - 273 = T°C

227.2K - 273 = -45.8°C

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expeople1 [14]
<h2>Answer:</h2>

In <u>Combination reaction</u>, two or more elements combined to form one compound of different properties.

  • C(s) + O2(g) ⇢ CO2(g).
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In <u>Displacement reation</u>, the high reactive element displaces the low reactive element and formed compound of different properties.

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8 0
2 years ago
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Which relationship can be used to aid in the determination of the heat absorbed by bomb calorimeter? 
NARA [144]

Answer:

ΔH = q_{p}

Explanation:

In a calorimeter, when there is a complete combustion within the calorimeter, the heat given off in the combustion is used to raise the thermal energy of the water and the calorimeter.

The heat transfer is represented by

q_{com} = q_{p}

where

q_{p} = the internal heat gained by the whole calorimeter mass system, which is the water, as well as the calorimeter itself.

q_{com}  = the heat of combustion

Also, we know that the total heat change of the any system is

ΔH = ΔQ + ΔW

where

ΔH = the total heat absorbed by the system

ΔQ = the internal heat absorbed by the system which in this case is q_{p}

ΔW = work done on the system due to a change in volume. Since the volume of the calorimeter system does not change, then ΔW = 0

substituting into the heat change equation

ΔH = q_{p} + 0

==> ΔH = q_{p}

5 0
3 years ago
Which element is found in period 6 group 14<br>​
kicyunya [14]

Answer:

Lead

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Explanation:

7 0
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A container is filled with a mixture of gases:
strojnjashka [21]

Answer:

The partial pressure of chlorine gas in the mixture is 1.55 atm.

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Partial pressure of oxygen gas = p_1=1.0 atm

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Using Dalton's law of partial pressure:

P=p_1+p_2+p_3

3.30 atm=1.0 atm+ 0.75 atm+p_3

p_3=3.30atm - (1.0 atm+ 0.75 atm)=1.55 atm

The partial pressure of chlorine gas in the mixture is 1.55 atm.

8 0
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