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3 years ago

How do the internal structures of vascular and plants transport food and water.

2 answers:

4 0

All vascular plants have vascular tissue which allows the transport of water, nutrients and food between the ground and the body of the plant. So your answer would be that the internal structures of vascular plants transport food and water through their vascular tissue. Hope this helps!

UkoKoshka [18]3 years ago

3 0

The Xylem transport water and minerals from the roots to the rest of the plant. While the Phloem transport food from the leaves to the rest of the plant. They both work with the internal structures of vascular and nonvascular plants transport food and water threw out the plant.

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Organic acids and bases in their ___________ form are soluble in organic solvents, but the corresponding _________ are more wate

gizmo_the_mogwai [7]

Answer:

a. neutral

b. salts

c. salt

Explanation:

Organic salts are a dense number of ionic compounds with innumerable characteristics. They are previously derived from an organic compound, which has undergone a transformation that allows it to be a carrier of a charge, and that in addition, its chemical identity depends on the associated ion.

Organic salts are usually stronger acids or bases than inorganic salts. This is because, for example, in the amine salts, it has a positive charge due to its bond with an additional hydrogen: A + -H. Then, in contact with a base, donate the proton to be a neutral compound again

RA + H + B => RA + HB

H belongs to A, but it is written as it is involved in the neutralization reaction.

On the other hand, RA + can be a large molecule, unable to form solids with a crystalline network stable enough with the hydroxyl anion or oxyhydrile OH–.

When this is so, salt RA + OH– behaves as a strong base; even as basic as NaOH or KOH

3 0

3 years ago

In the simple act of lighting a match, chemical energy stored in the match head is transformed into heat and light. What is true

harina [27]

The head of a matchstick has a great deal of chemical energy stored in it, including combustible substances that produce a flame when rubbed against a suitable surface. ... As the combustible materials burn, some of the chemical energy is transformed into heat energy, and some is transformed into light energy. Hope this helps

5 0

3 years ago

Read 2 more answers

The lightest weight element that is not a gas

LUCKY_DIMON [66]

Answer:Lithium

Explanation:Lithium has 3 protons, and 4 neutrons making it the lightest element that isn't a gas.

5 0

3 years ago

Read 2 more answers

. Determine the standard free energy change, ɔ(G p for the formation of S2−(aq) given that the ɔ(G p for Ag+(aq) and Ag2S(s) are

olga nikolaevna [1]

Answer: The standard free energy change of formation of $S^{2-}(aq.)$ is 92.094 kJ/mol

Explanation:

We are given:

$K_{sp}\text{ of }Ag_2S=8\times 10^{-51}$

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G^o=-RT\ln K$

where,

$\Delta G^o$ = standard Gibbs free energy = ?

R = Gas constant = $8.314J/K mol$

T = temperature = $25^oC=[273+25]K=298K$

K = equilibrium constant or solubility product = $8\times 10^{-51}$

Putting values in above equation, we get:

$\Delta G^o=-(8.314J/K.mol)\times 298K\times \ln (8\times 10^{-51})\\\\\Delta G^o=285793.9J/mol=285.794kJ$

For the given chemical equation:

$Ag_2S(s)\rightleftharpoons 2Ag^+(aq.)+S^{2-}(aq.)$

The equation used to calculate Gibbs free change is of a reaction is:

$\Delta G^o_{rxn}=\sum [n\times \Delta G^o_f_{(product)}]-\sum [n\times \Delta G^o_f_{(reactant)}]$

The equation for the Gibbs free energy change of the above reaction is:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(Ag^+(aq.))})+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times \Delta G^o_f_{(Ag_2S(s))})]$

We are given:

$\Delta G^o_f_{(Ag_2S(s))}=-39.5kJ/mol\\\Delta G^o_f_{(Ag^+(aq.))}=77.1kJ/mol\\\Delta G^o=285.794kJ$

Putting values in above equation, we get:

$285.794=[(2\times 77.1)+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times (-39.5))]\\\\\Delta G^o_f_{(S^{2-}(aq.))=92.094J/mol$

Hence, the standard free energy change of formation of $S^{2-}(aq.)$ is 92.094 kJ/mol

8 0

3 years ago

ddt, dde, pcbs and pbdes are all ________ddt, dde, pcbs and pbdes are all ________.a biodegradable and do not persist in the env

qwelly [4]

The answer is non-biodegradable and subject to bioaccumulation and/or bioamplification.

DDT (dichlorodiphenyltrichloroethane) is persistent, non-degradable insecticide and organic pollutant readily accumulated to soils and consequently affects organisms.
DDE (dichlorodiphenyldichloroethylene) is non-degradable pesticide toxic to birds at the first place.
PCBs (polychlorinated biphenyls) are non-degradable organic compounds very toxic to the environment.
PBDEs (polybrominated diphenyl ethers) are non-degradable compounds very toxic to environment, even able to affect brains of animals in the development period.

5 0

3 years ago