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pashok25 [27]
3 years ago
12

Summary the vegetables oil

Chemistry
1 answer:
alekssr [168]3 years ago
4 0

Introduction. Vegetable oils are a group of fats that are derived from some seeds, nuts, cereal grains, and fruits. ... Vegetable oils, as used in foods, are comprised of complex mixtures of triacylglycerols (TAGs; usually > 95%) with some minor amounts of diacylglycerols (usually < 5%).

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An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d = 1.114 g/ml; = 62.07 g/mol) and water (d
tankabanditka [31]
a) Volume percent

Formula: % v/v = [volume solute / volume solution] * 100

Just to make it easy take a base of 50 volume parts of ethylen glycol and 50 volume parts of water to make 100 volumes of mixture (this assumpion will be valid for all the questions):

% v/v =[ 50 ml ethyleneglycol] / [100 ml mixture] * 100 = 50%

Answer: 50% v/v

b) Mass percent

% m/m = [mass ethylene glycol / mass solution] * 100

mass ethylene glycol = 50 ml * 1.114 g/ ml = 55.7 g

mass of mixture = 100 ml * 1.07 g/ml = 107 g

% m/m = [55.7 / 107 g] * 100 = 52.06 %

Answer: 52.06%

c) Molarity

M = number of moles of solute / liters of solution

number of moles of solute = mass in grams / molar mass

number of moles of ehtylene glycol = 55.7 g / 62.07 g/mol = 0.8974 mol

liters of solution = 0.1 liter

M = 0.8974 mol / 0.1 liter = 8.974 M

Answer: 8.974 M

d) Molality

m = number of moles of solute / kg of solvent

number of moles of ethylen glycol = 0.8974 mol

mass of water = 50 ml * 1 g/ml = 50 g = 0.05 kg

m = 0.8974 mol / 0.05 kg = 17.95 m

Answer: 17.95 m

e) mole fraction

mole fraction = [number of moles of solute] / [number of moles of mixture] * 100

number of moles of ethylen glycol = 0.8974 mol

number of moles of water = 50 g / 18.01 g /mol = 2.776 mol

mole fraction = 0.8974 mol / [0.8974 mol + 2.776 mol] = 0.244

Answer: 0.244
7 0
3 years ago
Describes two uses of surfactants at least one must be something that was not described in the passage
Morgarella [4.7K]

Answer:

We don't have the passage.  A random sampling of surfactant uses includes:

  • removal of oily materials from objects (clothes and dishes)
  • forms remarkable structures called bubbles
  • Assists in forming emulsions (e.g., mayonaise and paints)

Explanation:

The structure of a surfactant makes one end of a molecule hydrophilic and the other end hydrophobic.  In water, they self-assemble into micelles, an arrangement in which the hydrophobic ends align towards the center, and the hydrophilic ends are pointed outwards to the water.  This self-assembly is apparant when bubbles are made.  The  molecules quickly align themselves such that the hyrophilic ends are oriented inwards towards a thin layer of water and the hydrophobic ends are pointed outward to the air.  This arrangement allows a mono-molecular sphere of water molecules to remain stable enough to float, reflect light, and please.  These same properties allow the inverse to occur.  Soap molecules surround a hydrophobic mass (e.g., the hamburger grease on your shirt) and solubilize it into small micelles which are then carried away in the surrounding water.

4 0
3 years ago
AN iron fence is left unpainted Nnd it's reacts with oxygen in the air these combine and form rust this is an example of
lidiya [134]

Chemical reaction...

6 0
3 years ago
is a polyprotic acid. Write balanced chemical equations for the sequence of reactions that carbonic acid can undergo when it's d
Burka [1]

Answer:

H₂CO₃   H₂O  ⇄  HCO₃⁻  +  H₃O⁺          Ka1

HCO₃⁻  +  H₂O  ⇄  CO₃⁻²  +  H₃O⁺        Ka2

CO₃⁻²  +  H₂O  ⇄  HCO₃⁻   +  OH⁻       Kb1

HCO₃⁻  +  H₂O  ⇄   H₂CO₃  +  OH⁻     Kb2

Explanation:

Formula for carbonic acid is: H₂CO₃

It is a dyprotic acid, because it can release two protons. We can also mention that is a weak one. The equilibrums are:

H₂CO₃   H₂O  ⇄  HCO₃⁻  +  H₃O⁺          Ka1

HCO₃⁻  +  H₂O  ⇄  CO₃⁻²  +  H₃O⁺        Ka2

When the conjugate strong bases, carbonate and bicarbonate take a proton from water, the reactions are:

CO₃⁻²  +  H₂O  ⇄  HCO₃⁻   +  OH⁻       Kb1

HCO₃⁻  +  H₂O  ⇄   H₂CO₃  +  OH⁻     Kb2

Notice, that bicarbonate anion can release or take a proton to/from water. This is called amphoteric,

6 0
3 years ago
A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree
victus00 [196]

Explanation:

The given data is as follows.

        q = 69.0 kJ = 69000 J (as 1 kJ = 1000 J),

       mass (m) = 8.10 kg = 8100 g  (as 1 kg = 1000 g)

        T_{i} = 33.9^{o}C = (33.9 + 273) K = 306.9 K

         C = 4.18 J/gK

As we know that the relation between heat and change in temperature is as follows.

                   q = m \times C \times \Delta T

Putting the values into the above formula to calculate the final temperature as follows.

                  q = m \times C \times \Delta T

       69000 J = 8100 g \times 4.18 J/g K \times (T_{f} - 306.9 K)                

           69000 J = 33858 \times (T_{f} - 306.9 K)

                  (T_{f} - 306.9 K) = 2.037 K

                    T_{f} = (2.037 + 306.9) K

                                  = 308.9 K

or,                               = 309 K (approx)

Thus, we can conclude that the new temperature of the water bath is 309 K.

5 0
3 years ago
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