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vitfil [10]
3 years ago
9

Determine which equations have the same solution set as StartFraction 2 Over 3 EndFraction minus x plus StartFraction 1 Over 6 E

ndFraction equals 6 x. – x + = 6x by recognizing properties, rather than solving. Check all that apply.
Mathematics
2 answers:
alex41 [277]3 years ago
6 0

Answer:

rfrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

Step-by-step explanation:

bezimeni [28]3 years ago
5 0

A B and f

Step-by-step explanation:

You might be interested in
What is the center and radius of the circle?
riadik2000 [5.3K]

Answer:

Center = (5,-3)     radius = sqrt (36) = 6

Step-by-step explanation:

4 0
2 years ago
OK so I have two questions to answer. So the first picture is question five in the second picture is question six.
Vesnalui [34]

Answer:

The slope is 2.25

The y-intercept is 3

Step-by-step explanation:

Assuming from the cut off picture, that we need to find the slope of ...

y=2.25x +3

y=mx+b form makes it easy to identify the slope and the y-intercept.

m is the slope and b is the y-intercept. Anything number that is in place of m, is the slope; and any nother in place of b is the y-intercept.

In that case, 2.25 is the slope and 3 is the y-intercept

3 0
3 years ago
Hector went shopping for a computer. At RST store, a computer originally prices at $955 had a price reduction of 40%. What was t
balandron [24]

Answer:

$573

Step-by-step explanation:

955* 0.60=573

or

10% of 955= 95.5

50% of 955=477.5

477.5=95.5=573

4 0
3 years ago
Determine the number of x-intercepts that appear on a graph of each function. f (x) = (x - 6)2(x + 2)2
Tpy6a [65]
<span>The number of x-intercepts that appear on the graph of  the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)


Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0

Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2

(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2

(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
6 0
3 years ago
Read 2 more answers
can someone explain it to me, i don't need the answer, i just need an detailed explanation of how they got the answer using the
zubka84 [21]

Answer:

Step-by-step explanation:

Good idea to review quadratic functions and the quadratic formula.

Quadratics have three coefficients:  ax² + bx + c, and the "discriminant" is defined as b²-4ac.  Please review these rules:

1) if the discriminant is +, the quadratic equation has two real, unequal roots.

2) if the disc. is 0, the equation has two real, equal root.

3) If the disc. is - , the equation has two complex roots.

Here a = 1, b  = -3 and c = 4.  Therefore the discriminant is (-3)²-4(1)(4), or

-7.  Rule 3) applies:  the equation has two complex roots, but no real ones.  Thus we know that the graph does not cross the x-axis.

Graphing the given quadratic, x² - 3x + 4, using a dashed "line," is helpful.  As you can see in the illustration of this graph, the graph neither touches nor crosses the x-axis.  Thus, y = x² - 3x + 4 is greater than 0 for all x.  The answer:  All real numbers.

4 0
3 years ago
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