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Wittaler [7]
3 years ago
15

A. greater than 1.b. less than 1.c. equal to 1

Mathematics
1 answer:
Zolol [24]3 years ago
5 0
A. 7/5, 16/10, 4/3

b. 3/10, 2/5, 1/3, 12/15

c. 3/3
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ryan rides his bicycle 5 miles in 3/4 hour. how many miles can he ride at the same rate in 1 hour? (in fractions)​
stepladder [879]

Answer:

20/3

Step-by-step explanation:

If Ryan rides his bike 5 miles in 3/4 of an hour, then he rides 5/3 miles in 1/4 of a hour (divide both by 3). To get to a full hour from 1/4, you need to multiply it by 4. You must do the same for 5/3. 5/3*4 is equal to 20/3.

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2 years ago
Can someone please answer this question?
MrMuchimi

Answer:

y = x - 3

Step-by-step explanation:

6 0
2 years ago
How many people must be in the group so that the probability of any two people sharing the same birthday is ~50%?
My name is Ann [436]

12345678912334567890123546789

4 0
3 years ago
According to exponent rules, when we multiply the expressions we __ the exponents
serious [3.7K]

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Add

Step-by-step explanation:

6 0
2 years ago
The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac
olya-2409 [2.1K]

Answer:

a) \frac{74}{10025}

b) \frac{3x-2}{x(8x+1)}

c) \frac{-24x^2+32x-2}{(8x^2+x)^2}

Step-by-step explanation:

For total cost function c(x), average cost is given by \frac{c(x)}{x} i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., \left ( \frac{c(x)}{x} \right )'

Given:c(x)=\frac{3x-2}{8x+1}

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

a)

At x = 50 units,

\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}

b)

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

c)

Marginal average cost:

Differentiate average cost with respect to x

Take f=3x-2\,,\,g=8x^2+x

using quotient rule, \left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}

Therefore,

\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}

3 0
3 years ago
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