Answer: a. 0.1031; fail to reject the null hypothesis
Step-by-step explanation:
Given: Significance level : 
The test statistic in a two-tailed test is z = -1.63.
The P-value for two-tailed test : 
[By p-value table]
Since, 0.1031 > 0.05
i.e. p-value > 
So, we fail to reject the null hypothesis. [When p< then we reject null hypothesis ]
So, the correct option is a. 0.1031; fail to reject the null hypothesis.
the answer is 13/7 and here is the correct question
the answer is 13/7 and here is the correct questionwhen a customer wants pie for dessert you cut a whole pies into 7 equal slices...at the end of your shift 3/7 of. a cherry pie.2/7. of an apple pie.3/7 of a peach pie.and 5/7 of a blueberry pie remain...How much pie remains as a fraction of. a whole pie...
Answer:
13/7
Step-by-step explanation:
From the question, we have
3/7 of cherry pie
2/7 of apple pie
3/7 of peach pie
5/7 of blueberry pie
Now we have to add up all of these in order to get the total amount of pie
3/7 + 2/7 +3/7 +5/7
= (3+2+3+5)/7
=13/7
If expressed as a mixed fraction
= 1 6/7
In conclusion, 13/7 pie remains as a fraction of a whole.
Answer:
AMY
BMY
BMX
Step-by-step explanation:
I took the assignment
Answer:
Step-by-step explanation:
A Chi-square test is used to test the test of independence between rows and columns, contingency tables. It is a test related to frequencies. The observed frequency is a given statistical frequency known as the actual frequency, the expected frequency is known as the theoretical frequency is derived from the study by using the sum total of the row and total in the column divided by their corresponding sample size.
Answer:
See explanation below.
Step-by-step explanation:
Having students in the classroom who are at different levels of knowledge, interest, and ability can be managed by differentiated instruction. This method is a way of thinking that provides a framework where the instructor can set students with learning tasks that are at levels appropriate with the abilities and interests of each student. Each student can have a different type of class and different type of instruction with the differentiated instruction way of thinking.
A gifted and talented student might be assigned a higher math course, perhaps based on a math assessment for advanced placement. Then students that need to stay on the typical high school path of Algebra I, Geometry, Algebra II, and Trigonometry can do that.
Gifted students might take an alternate path with honors classes or trajectories involving Pre-Calculus or advanced placement Calculus, for example. In some instances, universities have allowed High School students to obtain college credit for some courses taken during High School.
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