Answer:
this video may be helped to u
Step-by-step explanation:
https://youtu.be/3FMWXYebxL4
The formula is
I=prt
I interest earned 14.65
P initial deposit ?
R interest rate 0.025
T time 2 years
Plug in the formula
14.65=p×0.025×2
Solve for p
14.65=0.05p
Divide both sides by 0.05
P=14.65/0.05
P=293....answer
Hope it helps!
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer: y-8
Step-by-step explanation:
4c+3=15
You need to get rid of the 3
So you minus it from each side so you
4c=12
12/4=3
So c =3
