Answer:
gravitational potential enrgy
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Answer: the mass of methyl alcohol (CH3OH) in the sample is 0.0641 g
Explanation:
1. <u>Preliminars</u>;
- Molar mass of CH₃ OH: 32.04 g/mol
- Molar mass of C₂H₅OH: 46.07 g/mol
- Molar mass of CO₂: 44.01 g/mol
- Molar mass equation: molar mass = mass in grams / number of moles
2. <u><em>Algebraic equation # 1: mass of sample burned in terms of each reagent.</em></u>
3. <u><em>Algebraic equation # 2: mass of carbon dioxide produced in terms of each reagent</em></u>.
a) Combustion of methyl alcohol
- 2CH₃OH(l) + 3O₂(g) → 2CO₂(g) + 4H₂O(g)
- 2 × 32.04 g CH₃OH → 2 × 44.01 g CO₂
- Mass of CO₂ produced from M grams of CH₃OH = M / 32.04 × 44.01 = 1.374 M
b) Combustion of ethyl alcohol
- C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(g)
- 46.07 g CH₃OH → 2 × 44.01 g CO₂
- Mass of CO₂ produced from E grams of C₂H₅OH = E / 46.07 × 88.02 = 1.911 E
c) Mass of CO₂ (g) obtained, in terms of each reagent
- 1.374 M + 1.911 E = 0.386 ----- (2)
4) <u>System of equations</u>
- 1.374 M + 1.911 E = 0.386 ----- (2)
5) <u>Solution</u>
- From equation (1): E = 0.220 - M
- Substituting in equation (2): 1.374 M + 1.911 (0.220 - M) = 0.386
- 1.374 M + 0.4204 - 1.911 M = 0.386
- M = 0.0344 / 0.537 = 0.0641 g
Answer: the mass of methyl alcohol (CH3OH) in the sample is 0.0641 g
Answer:
It would appear that the H2 gas is collected in a stoppered flask. Therefore, the volume of the gas is 138 mL minus the 5 mL occupied by the HCl, or 133 mL.
Explanation:
Can you say that in English?
Answer:
As the gas is heated, the particles will begin to move faster. ... Because the gas remains at a constant pressure and volume, the particles cannot spread out so they simply move around the container even faster.
