Zn + 2 HCl --> ZnCl2 + H2 How many moles of hydrochloric acid (HCl) are used (assume a complete reaction) if 8.3 moles of zin c chloride (ZnCl) are produced? A 8.3 mol ZnCl2 B None of these answers C 8.3 mol HCl D 4.15 mol HCl E 16.6 mol HCl
1 answer:
Answer:
E. 16.6 mol HCl
Explanation:
The equation for the reaction is;
Zn + 2 HCl --> ZnCl2 + H2
From the reaction 2 moles of HCl produces 1 mole of ZnCl2
Therefore; 8.3 moles of ZnCl2 will be produced by;
= 8.3 moles ×2
= 16.6 Moles of HCl
Therefore; E. 16.6 mol HCl
You might be interested in
The change is called melting
Answer:
the particles, molecules, and gas range from smallest to largest in the following order: electron < proton < atom <...
Answer:
NH4+
Explanation:
NH4+ is the acid and NH3 is the base, so NH4+ is the stronger acid.
A. Protons, neutrons, and electrons
(the heat bomb calorimeter gained)=(the heat material A gave) r.h.s=25.57 kJ/⁰C * (26.80-24.33)= 63.16 kJ 2.741g of material A made 63.16kJ the heat of combustion per gram = 63.16/2.741 kJ/g =24.04kJ/g