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Diano4ka-milaya [45]
3 years ago
15

Zn + 2 HCl --> ZnCl2 + H2 How many moles of hydrochloric acid (HCl) are used (assume a complete reaction) if 8.3 moles of zin

c chloride (ZnCl) are produced? A 8.3 mol ZnCl2 B None of these answers C 8.3 mol HCl D 4.15 mol HCl E 16.6 mol HCl
Chemistry
1 answer:
uysha [10]3 years ago
4 0

Answer:

E. 16.6 mol HCl

Explanation:

The equation for the reaction is;

Zn + 2 HCl --> ZnCl2 + H2

From the reaction 2 moles of HCl produces 1 mole of ZnCl2

Therefore; 8.3 moles of ZnCl2 will be produced by;

  = 8.3 moles ×2

  = 16.6 Moles of HCl

  Therefore;  E.  16.6 mol HCl

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