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wel
3 years ago
14

Write the chemical formulas for the ionic compound vanadium (v) oxide

Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
5 0
V2O5 is the formula. Vanadium has a charge of +5 and oxygen is -2, so to make them equal, you need to double the vanadium charge and multiply the oxygen charge by 5
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Part 1: Fill in the blanks below to state Newton’s three laws of motion:
Rainbow [258]

Answer:

all objects will remain at rest, or will continue to move at a constant speed in the same velocity unless acted upon by an unbalanced force. This property is called interia

Explanation:

8 0
2 years ago
Explain the Anchoring Phenomenon (summary)
Virty [35]
An anchoring phenomenon anchors all of the learning within a unit. So, it is a unit level event that the classroom is trying to make sense of as they engage in a series of lessons.

Since the questions the students ask about the anchor drive the learning within the unit, the anchor should be complex and require an understanding of several big science ideas to explain.

At strategic moments, the class revisits the anchoring phenomenon to review their initial questions to see which they have answered, which they are making progress on, and what new questions they may have to help us continue learning about the phenomenon.

Throughout the unit, the classroom and each student should be given opportunities to share their thinking and how it relates to the anchoring phenomenon.
YOU SHOULD PUT IT IN YOUR OWN WORDS THOUGH <3
3 0
2 years ago
n an experiment, 39.26 mL of 0.1062 M NaOH solution was required to titrate 37.54 mL of \ v unknown acetic acid solution to a ph
olasank [31]

Answer:

Molarity: 0.111M

% (w/w): 0.666

Explanation:

The reaction of NaOH with acetic acid (CH₃COOH) is:

NaOH + CH₃COOH → CH₃COO⁻Na⁺ + H₂O

<em>where 1 mole of NaOH reacts per mole of acetic acid producing 1 mole of water and 1 mole of sodium acetate.</em>

As 39.26mL ≡ 0.03926L of 0.1062M are required to titrate the solution of acetic acid. Moles are:

0.03926L × (0.1062mol / L) = 4.169x10⁻³ moles of NaOH. As 1 mole of NaOH reacts per mole of acetic acid:

4.169x10⁻³ moles of CH₃COOH.

Molarity is defined as ratio between moles of substance and volume of solution in liters. Thus, molarity of acetic acid solution is:

4.169x10⁻³ moles of CH₃COOH / 0.03754L = <em>0.111M</em>

<em></em>

As molar mass of acetic acid is 60g/mol, 4.169x10⁻³ moles weights:

4.169x10⁻³ moles × (60g / mol) = <em>0.2501 g of acetic acid</em>

Now, assuming density of solution as 1.00g/mL, 37.54mL weights <em>37.54g</em>.

Thus, percent by weight is:

0.2501g CH₃COOH / 37.54g × 100 = <em>0.666% (w/w)</em>

8 0
2 years ago
17. Which solution is more concentrated?
Stella [2.4K]

Answer:

Solution 1.

Explanation:

We can find the concentration of a solution by looking at the ratio of the components.

In the first solution, there is a 500 mL:100g ratio. In the second, there is a 500mL:90g ratio. The greater ratio, or the ratio with a greater amount of solute in proportion to the water, is the first.

6 0
3 years ago
gasoline is separated from crude oil by heating it until it reaches it's boiling point. which separation method is used?​
Orlov [11]

Answer:

Fractional distillation

Explanation:

The separation of gasoline from crude oil by heating until it reaches its boiling point is a separation technique called fractional distillation.

  • It is the separation of a mixture, such as crude oil into their respective fractions.
  • This is achieved due to the differences in boiling point between the constituent fractions in the mixture.
  • As the boiling point of a fraction is reached, it distills out from the column.
4 0
3 years ago
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