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Katarina [22]
3 years ago
6

Which of these mixtures will MOST LIKELY result in soil? A) sand, clay, and heat B) sand, clay, and water C) sand, clay, heat, a

nd water D) sand, clay, water, and leaves
Chemistry
2 answers:
Wewaii [24]3 years ago
5 0

Answer:

I think it should be C.

Explanation:

Because for a plant to start photosinthesis it need sun (heat is like the sun),water,and stuff that soil is made of (sand and clay) tell me if this is correct

Thanks

Ulleksa [173]3 years ago
5 0

Answer:

Its D

Explanation:

because i took the test

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HELP HELP HELP HELP!!!!!!
suter [353]

Answer:

I think it is 100 if I guess

8 0
2 years ago
An object with a mass of 7.1 g raises the level of water in a graduated cylinder from 25.1 mL to 32.4 mL. What is the density of
jeka57 [31]

Answer:

0.9726g/ml

0.9726g/cm³

Explanation:

Density is found by dividing  mass by volume.

Density = mass/volume

mass = 7.1g

volume= the new level of water raised - the initial level of water

volume  = 32.4 - 25.1

volume = 7.3 ml

Volume is the amount of space occupied by an object.meaning the amount of volume displaced by the object is its volume.

density = 7.1 /7.3

density = 0.9726g/ml

or 0.9726 g/cm³

If you need any clarification or more explanation pls do mention at the comment section.

hope this helps and if it does pls mark as branliest answer thx

5 0
3 years ago
Iron-56, Iron-54, and Iron-58 are all ____ of iron
JulijaS [17]

Answer:

in the 50 place

Explanation:

3 0
3 years ago
Read 2 more answers
The si unit for measuring acceleration is?
ehidna [41]

m/s² aka meter per second squared.

acceleration = change in velocity/time  

= distance/time

--

time  

= m/s

--

s

=m/s^2

7 0
3 years ago
Read 2 more answers
To test the purity of sodium bicarbonate, you dissolve a 3.50g sample in water and add sulfuric acid. if 1.04g of carbon dioxide
Andrews [41]

Answer is: the percent purity of the sodium bicarbonate is 56.83 %.

1. Chemical reaction: 2NaHCO₃ + H₂SO₄ → 2CO₂ + 2H₂O + Na₂SO₄.

2. m(NaHCO₃) = 3.50 g

n(NaHCO₃) = m(NaHCO₃) ÷ M(NaHCO₃).

n(NaHCO₃) = 3.50 g ÷ 84 g/mol.

n(NaHCO₃) = 0.042 mol.

3. From chemical reaction: n(NaHCO₃) : n(CO₂) = 1 : 1.

n(CO₂) = 0.042 mol.

m(CO₂) = 0.042 mol · 44 g/mol.

m(CO₂) = 1.83 g.

4. the percent purity = 1.04 g/1.83 g  ·100%.

the percent purity = 56.8 %.

8 0
3 years ago
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