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3 years ago

A straight piece of wire is collided to form a spring physical or chemical change

Chemistry

2 answers:

spayn [35]3 years ago

7 0

Physical because it is still a wire and it has only changed form.

a_sh-v [17]3 years ago

4 0

This would be a physical change.

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Which electromagnet would have the most strength?

ycow [4]

The one with 20 coils as it can generate more electricity.

8 0

3 years ago

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Carbon-14 naturally decays to carbon

barxatty [35]

Answer:

Carbon-14 naturally decays to Carbon-12

Explanation:

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3 years ago

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Concentrated hydrochloric acid is made by pumping hydrogen chloride gas into distilled water. If concentrated HCl contains 439 g

Elza [17]

Answer:

12.10 mol / 1 L

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity ( unit = mol / L or M )

V = volume of solution in liter ( unit = L ),

n = moles of solute ( unit = mol ),

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

The data given is as follows -

w = 439 g

As , we known for HCl ,

m = 36.46 g/mol

V = 1 L

From the above data ,

Moles are given as -

n = w / m

n = 439 / 36.26 = 12.10 mol ,

Now , the molarity is given as ,

M = n / V

M = 12.10 mol / 1 L

M = 12.10 mol /L

7 0

3 years ago

Acetylene gas (C2H2) is used in welding torches. When it reacts with oxygen, it produces

Vikki [24]

Mass C₂H₂ needed : 22.165 g

<h3>Further explanation</h3>

Reaction

2C₂H₂+ 5O₂ ⇒ 4CO₂ + 2H₂O

75.0 grams of CO₂ , mol CO₂ (MW=44 g/mol) :

$\tt \dfrac{75}{44}=1.705$

mol C₂H₂ :

$\tt \dfrac{2}{4}\times 1.705=0.8525$

mass C₂H₂ (MW=26 g/mol) :

$\tt 0.8525\times 26=22.165~g$

8 0

3 years ago

Now let us refine our model by noting that there is a second source of Na+ ions in the cell: NaI. Suppose the outside of the cel

MArishka [77]

Answer:

$E=55mV$

Explanation:

Hello,

Considering the given information, the new concentration of Na+inside will be (13.6 + 4) mM = 17.6 mM, and outside will be (150 + 0.04) mM = 150.04 mM due to the previous specified conditions.

Now, the recalculation of the Nerst potential at the supposed temperature of 25 °C (which is modifiable) is done via:

$E=\frac{RT}{zF} ln(\frac{C_{Na^+,outside}}{C_{Na^+,outside}} )\\\\E=\frac{8.314\frac{J}{mol*K}*298K}{1*9.65x10^4\frac{C}{mol} } *ln(\frac{150.04}{17.6} )=0.055V*\frac{1x10^3mV}{1V} \\E=55mV$

Best regards.

8 0

3 years ago