I'm NOT 100% confident in my answers.
Graph 1:
Range: Option B
Graph 2:
Range: Option A
The range has to start at zero since that's the lowest point we can go, only one with zero is first option.
RATE AS BRAINLIEST
We have a line tangent to the circle with center B at point C. We know that the angle formed between the tangent line at the point of intersection to the line extended from that point to the center of the circle is equal to 90°. In the problem, the 90° is for ∠BCA. We also know that the summation of all angles in a triangle is 180°. We have the solution below for the ∠BAC
180°=∠BAC + ∠BCA + ∠ABC
180°=∠BAC + 90° + 40°
∠BAC =50°
The answer is 50°.
Answer:
<u>There</u><u> </u><u>is</u><u> </u><u>no</u><u> </u><u>solution</u>
Answer:
279 feet
Step-by-step explanation:
To find x, we solve using the Trigonometric function of Tangent
tan θ = Opposite/ Adjacent
θ = 64°
Length of the shadow = Adjacent = 136 feet
Height of the building = Opposite = h
Hence,
tan 64 = h/136 feet
Cross Multiply
h = tan 64 × 136 feet
h = 278.84132245 feet
Approximately, h to the nearest foot ≈ 279 feet
Therefore, the height of the building = 279 feet
