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In-s [12.5K]
4 years ago
13

How much work must be done by frictional forces in slowing a 1000-kg car from 26.1 m/s to rest?

Physics
1 answer:
Semmy [17]4 years ago
3 0

Answer:

Explanation:

Work done by the frictional force is 3.41x10^5 J

It is given that,

Mass of the car, m = 1000 kg

Initial velocity of car, u = 26.1 m/s

Finally, it comes to rest, v = 0

We have to find the work done by the frictional forces. Work done is equal to the change in kinetic energy as per work - energy theorem i.e.

W = −340605 J

or Hence, the correct option is (a).

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The last word is gear
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Based on observations, the speed of a jogger can be approximated by the relation v 5 7.5(1 2 0.04x) 0.3, where v and x are expre
castortr0y [4]

Answer:

solution:

to find the speed of a jogger use the following relation:  

V

=

d

x

/d

t

=

7.5

×m

i

/

h

r

...........................(

1

)  

in Above equation in x and t. Separating the variables and integrating,

∫

d

x

/7.5

×=

∫

d

t

+

C

or

−

4.7619  

=

t

+

C

Here C =constant of integration.   

x

=

0  at  t

=

0

, we get:  C

=

−

4.7619

now we have the relation to find the position and time for the jogger as:

−

4.7619  =

t

−

4.7619

.

.

.

.

.

.

.

.

.

(

2

)

Here

x  is measured in miles and  t  in hours.

(a) To find the distance the jogger has run in 1 hr, we set t=1 in equation (2),    

     to get:

      = −

4.7619  

      =  

1

−

4.7619

      = −

3.7619

  or  x

=

7.15

m

i

l

e

s

(b) To find the jogger's acceleration in   m

i

l

/

differentiate  

     equation (1) with respect to time.

     we have to eliminate x from the equation (1) using equation (2).  

     Eliminating x we get:

     v

=

7.5×

     Now differentiating above equation w.r.t time we get:

      a

=

d

v/

d

t

       =

−

0.675

/

      At  

      t

=

0

      the joggers acceleration is :

       a

=

−

0.675

m

i

l

/

        =

−

4.34

×

f

t

/  

(c)  required time for the jogger to run 6 miles is obtained by setting  

        x

=

6  in equation (2).  We get:

        −

4.7619

(

1

−

(

0.04

×

6  )

)^

7

/

10=

t

−

4.7619

         or

         t

=

0.832

h

r

s

6 0
3 years ago
If an orange falls off the table, what causes it to stop?​
emmasim [6.3K]

The floor or chair absorbing the force of the impact from the orange causes the orange to stop.

7 0
3 years ago
What is the mass of 3.70 L of water? Remember 1000 L = 1 m^3 (Unit=Kg)
xxMikexx [17]

Answer:

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Explanation:

The following data were obtained from the question:

Volume = 3.7L

Mass =?

Next, we shall convert 3.7L to m³.

This is illustrated below:

1000L = 1m³

Therefore, 3.7L = 3.7/1000 = 0.0037m³

Now, we can obtain the mass of the water as shown below:

Density of water = 1000kg/m³

Volume of water = 0.0037m³

Mass of water =..?

Density = Mass /volume

1000kg/m³ = Mass /0.0037m³

Cross multiply

Mass = 1000Kg/m³ × 0.0037m³

Mass = 3.7Kg

Therefore, the mass of the water is 3.7Kg.

8 0
3 years ago
The subfield of anthropology that describes, analyzes, interprets, and explains social and cultural similarities and differences
Makovka662 [10]

Answer:

cultural

Explanation:

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6 0
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