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3 years ago

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Can someone help me dontk

1 answer:

Mnenie [13.5K]3 years ago

6 0

I don't know what you meant 'dontk'.

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Which terms describe the motion of most objects in our solar system?

olga2289 [7]

Answer:Geography, Earth Science, Astronomy

Rotation describes the circular motion of an object around its center.

Explanation:

6 0

3 years ago

Read 2 more answers

Problem One: A beam of red light (656 nm) enters from air into the side of a glass and then into water. wavelength, c. and speed

Ivanshal [37]

Answer:

Part a)

$f_w = f_g = 4.57 \times 10^{14} Hz$

Part b)

$\lambda_w = 492 nm$

$\lambda_g = 437.3 nm$

Part c)

$v_w = 2.25 \times 10^8 m/s$

$v_g = 2.0 \times 10^8 m/s$

Explanation:

Part a)

frequency of light will not change with change in medium but it will depend on the source only

so here frequency of light will remain same in both water and glass and it will be same as that in air

$f = \frac{v}{\lambda}$

$f = \frac{3 \times 10^8}{656 \times 10^{-9}}$

$f = 4.57 \times 10^{14} Hz$

Part b)

As we know that the refractive index of water is given as

$\mu_w = 4/3$

so the wavelength in the water medium is given as

$\lambda_w = \frac{\lambda}{\mu_w}$

$\lambda_w = \frac{656 nm}{4/3}$

$\lambda_w = 492 nm$

Similarly the refractive index of glass is given as

$\mu_w = 3/2$

so the wavelength in the glass medium is given as

$\lambda_g = \frac{\lambda}{\mu_g}$

$\lambda_g = \frac{656 nm}{3/2}$

$\lambda_g = 437.3 nm$

Part c)

Speed of the wave in water is given as

$v_w = \frac{c}{\mu_w}$

$v_w = \frac{3 \times 10^8}{4/3}$

$v_w = 2.25 \times 10^8 m/s$

Speed of the wave in glass is given as

$v_g = \frac{c}{\mu_g}$

$v_g = \frac{3 \times 10^8}{3/2}$

$v_g = 2 \times 10^8 m/s$

4 0

4 years ago

What space agency is predicted to be first to Mars?

zzz [600]

SpaceX(NASA).

America is the greatest.

7 0

3 years ago

Years ago, a block of ice with a mass of about 20.0 kg was used daily in a home icebox. The temperature of the ice was 0.0°C whe

m_a_m_a [10]

Answer: The ice absorb 6671.1 kJ of thermal energy.

Explanation:

The conversions involved in this process are :

$0.00^0C=273K$

$:H_2O(s)(273K)\rightarrow H_2O(l)(273K)$

Now we have to calculate the enthalpy change.

$\Delta H=n\times \Delta H_{fusion}$

where,

$\Delta H$ = enthalpy change = ?

m = mass of ice = 20.0 kg = $20.0\times 10^3g$ (1kg=1000g)

n = number of moles of ice= $\frac{\text{Mass of ice}}{\text{Molar mass of water}}=\frac{20.0\times 10^3g}{18g/mole}=1.11\times 10^3mole$

$\Delta H_{fusion}$ = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

Now put all the given values in the above expression, we get

$\Delta H=1.11\times 10^3mole\times 6010J/mole$

$\Delta H=6671100J=6671.1kJ$ (1 kJ = 1000 J)

Therefore, the enthalpy change is, 6671.1 kJ

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3 years ago

Can someone provide help for this question?

Aleksandr-060686 [28]

Answer: conduction

Explanation: i think so sorry if im wrong im reallly sorry

7 0

3 years ago