8.How long is a day? A year?

A small glider is placed against a compressed spring at the bottom of an air track that slopes upward at an angle of 39.0 ∘ abov

zvonat [6]

Answer:

kinetic energy of glider = -0.376 j

Explanation:

Original distance by which the spring is compressed can be determine by using law of conservation of energy (As spring slide from glider, it gain some potential energy. On the top of track there is glider’s potential energy exist)

$\frac{1}{2} kx^2 = mgh$

where x is compressed distance by spring

height of track is calculated as

$sin\theta \frac{h}{l}$

$h = l sin\theta$

where l is distance covered by glider, theta angle is the angle of inclination of track

therefore, we have formula for x as

$x = \sqrt{\frac{2mglsin\theta}{k}}$

$x = \sqrt{\frac{2\times 0.05 \times 9.8 \times 1.50\times sin39}{600}}$

x = 0.039 m

kinetic energy of glider = potential energy by spring - potential energy at 1.50 distance

$=( \frac{1}{2} \times 600\times 0.039^2) - (0.05 \times 9.8 \times 1.5 \times sin 39)$

kinetic energy of glider = -0.376 j

8 0

4 years ago

An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a ra

lukranit [14]

Answer:

$\frac{dA}{dt} = 28800 \ m^2/year$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Geometry

Area of a Rectangle: A = lw

Algebra I

Exponential Property: $w^n \cdot w^m = w^{n + m}$

Calculus

Derivatives

Differentiating with respect to time

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Explanation:

Step 1: Define

Area is A = lw

2w = l

w = 300 m

$\frac{dw}{dt} = 24 \ m/year$

Step 2: Rewrite Equation

Substitute in l: A = (2w)w
Multiply: A = 2w²

Step 3: Differentiate

Differentiate the new area formula with respect to time.

Differentiate [Basic Power Rule]: $\frac{dA}{dt} = 2 \cdot 2w^{2-1}\frac{dw}{dt}$
Simplify: $\frac{dA}{dt} = 4w\frac{dw}{dt}$

Step 4: Find Rate

Use defined variables

Substitute: $\frac{dA}{dt} = 4(300 \ m)(24 \ m/year)$
Multiply: $\frac{dA}{dt} = (1200 \ m)(24 \ m/year)$
Multiply: $\frac{dA}{dt} = 28800 \ m^2/year$

3 0

3 years ago

Read 2 more answers

For a centrifugal compressor, the flow at the exit of the blade (state 2) has a velocity of 250 m/s with an angle of 15 degrees

shtirl [24]

The velocity at the end of vaneless space(state 3) is 965.92 m/s

<h3>What is centrifugal compressor?</h3>

It increases kinetic energy to the airstream using a rotating element and then converts it into potential energy in the form of pressure.

Temperature at state 2, T₂ =T₀ + c/2Cp

Substitute T₀ =450K, c=250m/s, Cp =1005, we get

T₂ =418.90K

From the velocity triangle, sinβ₂ =c₂/v₂

v₂ = 250/sin (90°-75°) = 965.92 m/s

Thus, the velocity at the end of vaneless space is 965.92 m/s.

Learn more about centrifugal compressor.

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6 0

3 years ago

During the Moment of Inertia experiment, a group of students decided to mount a solid sphere on the top of the horizontal disk.

bekas [8.4K]

Answer:

u are the very good person I know if u will do itself u will becam3 a rising star

8 0

3 years ago

What is the difference between charging by contact and charging by induction in terms of electron transfer.

Veronika [31]

Answer:

the main difference between charging by contact and charging by induction is that in the first case, the two objects are touching, while in the second case, the two objects do not touch

Explanation:

There are three methods of charging an object:

- Charging by friction: this is done by rubbing an object against another object. An example is when a plastic rod is rubbed with a wool cloth. When this is done, electrons are transferred from the wool to the rod, so both objects remain charged at the end of the process

- Charging by contact: this is done by putting in contact a charged object with a neutral, conducting object. In this case, the charges are transferred from the charged object to the neutral object; at the end of the process, the neutral object will also have a net electric charge, so it will be also charged.

- Charging by induction: in this case, we take a charged object, and a neutral object, and we place the two objects close to each other, but without touching. Let's assume that the charged object is negatively charged: in this case, the positive charges in the neutral object are attracted towards the negative charges of the charged object, while the negative charges of the neutral object are repelled away. As a result, the positive and negative charges in the neutral object split apart. If the object is connected to the ground, then negative charges move away, so the neutral object will remain positively charged.

Therefore, the main difference between charging by contact and charging by induction is that in the first case, the two objects are touching, while in the second case, the two objects do not touch.

5 0

3 years ago