If a sound wave is produced with a wavelength of 1.04m what is the waves frequency

What is the average translational KE of 5 moles of gas molecules at 300 K?

aev [14]

Answer:

What is the average translational kinetic energy of molecules in an ideal gas at 37°C? The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.

Explanation:

The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.

7 0

3 years ago

A 29.0-kg block is initially at rest on a horizontal surface. A horizontal force of 71.0 N is required to set the block in motio

Julli [10]

Answer:

(a) $\mu_s=0.25$

(b) $\mu_k=0.20$

Explanation:

According to Newton's second law:

$\sum F_y:N=mg\\\sum F_x:F_a=F_f$

Recall that the frictional force is related jointly with the coefficient of friction and normal force $F_f=\mu N$ . Replacing in the above equation, we get the coefficient of friction:

$F_a=\mu N=\mu mg\\\mu=\frac{F_a}{mg}$

(a) The coefficient of static friction is related with the force required to set the block in motion:

$\mu_s=\frac{71N}{29kg*9.8\frac{m}{s^2}}\\\mu_s=0.25$

(b) The coefficient of kinetic friction is related with the force required to keep the block moving with constant speed:

$\mu_k=\frac{56N}{29kg*9.8\frac{m}{s^2}}\\\mu_k=0.20$

3 0

3 years ago

Calculate the wavelength and frequency at which the intensity of the radiation is a maximum for a blackbody at 298 K. You will n

Juliette [100K]

Answer:

Wavelength, $\lambda=9.72\times 10^{-6}\ m$

Frequency, $f=3.08\times 10^{13}\ Hz$

Explanation:

We need to find the intensity of the radiation is a maximum for a black body at 298 K. It can be calculated using Wein's displacement law. It is given by :

$\lambda T=2.898\times 10^{-3}\ m-K$

$\lambda=\dfrac{2.898\times 10^{-3}}{T}$

Here, T = 298 K

$\lambda=\dfrac{2.898\times 10^{-3}}{298}$

$\lambda=9.72\times 10^{-6}\ m$

If f is the frequency of black body radiation. It is given by :

$f=\dfrac{c}{\lambda}$

$f=\dfrac{3\times 10^8}{9.72\times 10^{-6}}$

$f=3.08\times 10^{13}\ Hz$

Hence, this is the required solution.

6 0

3 years ago

Which energy transformation pops the corn kernels

Andrews [41]

Answer:

heat?

Explanation:

3 0

3 years ago

The dancing bear family loves when their trainer gives them little treats to reward them for a good performance. If the trainer

lions [1.4K]

Answer:

748 treats.

Explanation:

If the trainer gives out 34 treats and gave them out for 22 shows, then to find the total you need to multiply 34 by 22, or (a longer but more simple way) add 34, 22 times.

5 0

3 years ago