Answer:
Explanation:
THE CORECT QUESTION
A 50.0 mL solution of 0.127 M KOH is titrated with 0.254 M HCl. Calculate the pH of the solution after the addition of each of the given amounts of HCl.
SOLUTION
Get the concentration of the HCl first using titration formula
CA X V A / CB VB = NA/ NB
Equation of reation; KOH + HCl => KCl + H2O
CA = 0.254 M
CB = 0.127
VA = 1/0.254 = 3.937
CA (after the addition) = 0.127 x 50 / 3.937
= 1.612 M
But pH = - Log[hydrogen ion]
= -log 1.612
=
Note: You are calculating mass which is determine the gram(g)
You will have to cancel out the mol
(28.97 g/mol) * mol will give grams by itself
Given the mass 3.33 moles of air
28.97 g/mol * 3.33 mol = 96.47 grams
Solution: 96.5 grams
18 is the max number of electrons in 1 orbital
i will ans the 2nd part first:
heat sources 4 homes: those wuld be renewable resources that generate heat. They include geothermal, solar water-heating and bio-mass.
primarily produce electricity: those wuld be something that is big like a dam for hydroelectric, wind turbine for electric generation, and solar farm for electricity.
Nobles gases, since they all have 8 e- on their last layer of electrons.