Answer:
based on this ball and stick model how many oxygen atoms are there in a milecule of 2 propanol
Explanation:
You have molarity and you have volume. Use the formula :
Molarity(M)= Moles(N)/Liter(L) to get the solution.
150 ml= .150 L
7.7 = N/.150
N=.1.155 moles of NaOH.
And since you know the moles, use the molar mass to figure out the grams.
<span> (40g/mol NaOH) x (1.155mol) =
46.2 g of NaOH.</span>
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Answer:
Absorbing beta particle because the beta is the numbers and are less and the big numbers are positive and they are the alpha so when you add beta particle it is called Absorbing so the answer is Absorbing beta particle
In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=
![( \frac{3(12 g/mol)}{3(12 g/mol)+6(1 g/mol)+16 g/mol} ) x 100%](https://tex.z-dn.net/?f=%28%20%5Cfrac%7B3%2812%20g%2Fmol%29%7D%7B3%2812%20g%2Fmol%29%2B6%281%20g%2Fmol%29%2B16%20g%2Fmol%7D%20%29%20x%20100%25)
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%