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Pani-rosa [81]
3 years ago
8

1, If the “R” under the group title represent the elements in that group, then how any atoms of Na (sodium) will react with 1 at

om of O (oxygen).
2. If the “R” under the group title represent the elements in that group, then how any atoms of Na (sodium) will react with 1 atom of H (hydrogen).

Chemistry
1 answer:
goblinko [34]3 years ago
5 0

Answer:

NaH one atom of sodium react with one hydrogen to form sodium hydride

Explanation:

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I agree with the person on top have a beautiful day:)
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3 years ago
Identify the true statement(s). There may be one answer or more than one answer.FADH2 is a reducing agent. FADH2 is an oxidizing
adell [148]

Answer:

FADH2 is a reducing agent.

FAD is an oxidizing agent.

Explanation:

The full form of FAD is flavin adenine dinucleotide. It is mainly a redox-active coenzyme which is associated with the different proteins and is involved with the enzymatic reactions in the metabolism.

FAD is obtained by donating or accepting electrons.

In the citric acid cycle,

succinate + FAD → fumarate + $FADH_2$

Thus we see that FAD is an oxidizing agent while $FADH_2$ is a reducing agent.      

8 0
3 years ago
The teal line of the hydrogen emission spectrum has a wavelength of 486.0 nm. A hydrogen emission spectrum has a violet, a blue,
Sloan [31]

Answer:

The correct answer to the following question will be "4.08 × 10⁻¹⁹ Joule".

Explanation:

Given:

Wavelength, λ = 486.0 nm

As we know,

E=h\upsilon =\frac{hc}{\lambda}

On putting the estimated values, we get

⇒          =\frac{1241.5 \ ev\ nm}{486 \ nm}

⇒          =2.554 \ ev

∴ 1 ev = 1.6 × 10⁻¹⁹ J

Now,

Energy, E=2.554\times 1.6\times 10^{-19}

⇒               =4.08\times 10^{-19} Joule

7 0
3 years ago
Calculate the mass of 3.5 mol C6H6
Lilit [14]
(3.5mol)(24.106 g/1mol c6h6) =84.371 g C6H6
4 0
3 years ago
5.6 g of solid CO2 is put in an empty sealed 4.00 L container at a temperature of
tresset_1 [31]

Answer:

0.78 atm

Explanation:

Step 1:

Data obtained from the question. This includes:

Mass of CO2 = 5.6g

Volume (V) = 4L

Temperature (T) =300K

Pressure (P) =?

Step 2:

Determination of the number of mole of CO2.

This is illustrated below:

Mass of CO2 = 5.6g

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Number of mole CO2 =?

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 5.6/44

Number of mole of CO2 = 0.127 mole

Step 3:

Determination of the pressure in the container.

The pressure in the container can be obtained by applying the ideal gas equation as follow:

PV = nRT

The gas constant (R) = 0.082atm.L/Kmol

The number of mole (n) = 0.127 mole

P x 4 = 0.127 x 0.082 x 300

Divide both side by 4

P = (0.127 x 0.082 x 300) /4

P = 0.78 atm

Therefore, the pressure in the container is

3 0
3 years ago
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