2 years ago

The dictionary from #2 falls off the table. How much kinetic energy does it have just before it hits the floor?

Chemistry

1 answer:

lys-0071 [83]2 years ago

7 0

Answer:

um a lot

Explanation:

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6 0

2 years ago

Pls help ty so much!

Nitella [24]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:mass = 11.42 \:\: grams$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: Q = ms\Delta T$

$\textsf{Q = heat evolved/absorbed = 501 J}$

$\textsf{m = mass in gram = ?}$

$\textsf{s = specific heat = 0.45}$

$\textsf{ΔT = change in temp = 120 - 22.5 =97.5°C}$

$\large\textsf{Find m : }$

$\qquad \tt \rightarrow \: 501 = m \sdot(0.45) \sdot(97.5)$

$\qquad \tt \rightarrow \: 501 = m \sdot43.875$

$\qquad \tt \rightarrow \: m = \dfrac{501}{43.875}$

$\qquad \tt \rightarrow \: m \approx11.42 \: \: g$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0

1 year ago

Which equation shows how to calculate how many grams (g) of KOH would be needed to fully react with 4 mol Mg(OH)2? The balanced

bazaltina [42]

Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
moles KOH ------------------- 4 moles Mg(OH₂)

moles KOH = 4 x 2 / 1

= 8 moles of KOH

molar mass KOH = 56 g/mol

mass of KOH = n x mm

mass of KOH = 8 x 56

= 448 g of KOH

hope this helps!

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3 years ago

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