3 years ago

why is it important for scientists to have a standard measurement system that is used around the world

Physics

1 answer:

natka813 [3]3 years ago

8 0

So they can easily communicate with other scientists.

Be sure to rate me up and give me a thanks :D

You might be interested in

Which source of energy would you prefer for cooking and why?

timurjin [86]

Answer:

gas

Explanation:

because It is fast and easy

3 0

4 years ago

true or false: a image created by an object located inside the focal point is virtual, enlarged, and upright

crimeas [40]

true or false: a image created by an object located inside the focal point is virtual, enlarged, and upright

True :D

4 0

3 years ago

X<br> x<br> 2.5 N<br> 1.7 N<br> 2.5 N

Olin [163]

Answer:

2.5*1.7/2.5

Explanation:

6 0

3 years ago

?????Help please?????

Sindrei [870]

The correct selections are C, C, B, D, A, B, and A .

6 0

4 years ago

A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.50 Ω is in a 1.0 mT magnetic field, with the coil orien

n200080 [17]

Answer:

The voltage across the capacitor is 1.57 V.

Explanation:

Given that,

Number of turns = 10

Diameter = 1.0 cm

Resistance = 0.50 Ω

Capacitor = 1.0μ F

Magnetic field = 1.0 mT

We need to calculate the flux

Using formula of flux

$\phi=NBA$

Put the value into the formula

$\phi=10\times1.0\times10^{-3}\times\pi\times(0.5\times10^{-2})^2$

$\phi=7.85\times10^{-7}\ Tm^2$

We need to calculate the induced emf

Using formula of induced emf

$\epsilon=\dfrac{d\phi}{dt}$

Put the value into the formula

$\epsilon=\dfrac{7.85\times10^{-7}}{dt}$

Put the value of emf from ohm's law

$\epsilon =IR$

$IR=\dfrac{7.85\times10^{-7}}{dt}$

$Idt=\dfrac{7.85\times10^{-7}}{R}$

$Idt=\dfrac{7.85\times10^{-7}}{0.50}$

$Idt=0.00000157=1.57\times10^{-6}\ C$

We know that,

$Idt=dq$

$dq=1.57\times10^{-6}\ C$

We need to calculate the voltage across the capacitor

Using formula of charge

$dq=C dV$

$dV=\dfrac{dq}{C}$

Put the value into the formula

$dV=\dfrac{1.57\times10^{-6}}{1.0\times10^{-6}}$

$dV=1.57\ V$

Hence, The voltage across the capacitor is 1.57 V.

5 0

4 years ago