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Alekssandra [29.7K]
3 years ago
6

A car tire rotates with an average angular speed of 29 rad/s. In what time interval will the tire rotate 3.5 times? ​

Physics
1 answer:
meriva3 years ago
8 0

Answer:

"0.758315 sec" is the appropriate choice.

Explanation:

The given values are:

Angular speed,

= 29 rad/s

or,

= \frac{29}{2 \pi} \ rps

Tire rotates,

= 3.5 times

Now,

The time interval will be:

⇒  \Delta t=\frac{3.5}{\frac{29}{2 \pi} }

⇒       =\frac{2 \pi\times 3.5}{29}

⇒       =\frac{21.99}{29}

⇒       =0.758315 \ sec

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The force of friction is a necessary force which helps us to walk on ground. The friction is generated between the shoes and the road. We press the ground and as a reaction the ground pushes us forward. The force of friction between sole and ground provides the necessary grip which pushes us forward

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b. The internal resistance must be much smaller than the other resistances in the circuit.

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A 1.0-μm-diameter oil droplet (density 900 kg/m3) is negatively charged with the addition of 39 extra electrons. It is released
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Answer:

6.75\mu C/m^2

Explanation:

We are given that

Diameter,d=1\mu m=1\time 10^{-6} m

1\mu m=10^{-6} m

Radius,r=\frac{d}{2}=\frac{1}{2}\times 10^{-6}=0.5 \times 10^{-6} m

Density,\rho=900kg/m^3

Total number of electrons,n=39

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Total charge=q=ne=39\times 1.6\times 10^{-19}=62.4\times 10^{-19} C

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Final speed,v=4.5 m/s

v^2-u^2=2as

(4.5)^2-0=2a(2\times 10^{-3})

20.25=4a\times 10^{-3}

a=\frac{20.25}{4\times 10^{-3}}=5062.5m/s^2

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qE=ma

q(\frac{\sigma}{2\epsilon_0})=ma

\sigma=\frac{2\epsilon_0ma}{q}=\frac{2\times 8.85\times 10^{-12}\times 4.7\times 10^{-16}\times 5062.5}{62.4\times 10^{-19}}

\epsilon_0=8.85\times 10^{-12}

\sigma=6.75\times 10^{-6}C/m^2=6.75\mu C/m^2

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