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3 years ago

What is the measure of a specific material’s ability to insulate charges from each other?

Physics

2 answers:

Leya [2.2K]3 years ago

4 0

B . dielectric constant

Elodia [21]3 years ago

3 0

B.dielectric constant

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Which describes a reflected image in a plane mirror?

Paul [167]

Answer:

B. The image is right-left reversed and about as far away from the mirror as the reflected object.

Explanation:

A plane mirror is used in several ways in our life, from the mirror that we have on the bathroom to the mirrors we use on cars, the main difference is that the mirror reflects the image reversed on the Vertical axis, which means that the left is the right and the right is the left, a mirror also protrays objects at a certain distance, about as far away from the mirror as the reflected object but they are actually closer in real life.

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3 years ago

In object of mass 30 kg is in freefall in a vacuum where there is no air resistance determine the acceleration of the object

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The free fall acceleration due to the Earth's gravity will always be 9.8m/s^2. So, if this question is taking place on Earth, then the acceleration of an object in free fall is 9.8m/^2.

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3 years ago

A circuit has a current of 1.2 A. If the voltage decreases to one-third of its original amount while the resistance remains

beks73 [17]

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2 years ago

The area vector of a square loop of 5 turns of a conductor each with side length of 0.2 m carrying a current of 2 A is antiparal

Anon25 [30]

Answer:

$M= 0.4 Am^2$

Explanation:

From the question we are told that:

Number of turns $N=5$ $N=5$

Conductor each with side length $L=0.2m$

Current $I=2A$

Magnetic field $B=50.0T$

Generally the equation for the total magnetic moment M is mathematically given by

$M = current * area$

$M= I * A$

$M = 2 * (5* 0.2*0.2)$

$M = 2 * 0.2$

$M= 0.4 Am^2$

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2 years ago

Two 13 cm -long thin glass rods uniformly charged to +11nC are placed side by side, 4.0 cm apart. What are the electric field st

DedPeter [7]

Answer:

E1 = 10.15 * 10^4 N/C

E2 = 0

E3 = 10.15 *10^4 N/C

Explanation:

Given data:

Two 13 cm-long thin glass rods ( L ) = 0.13 m

charge (Q) = +11nC

distance between thin glass rods = 4 cm .

<u>Calculate the electric field strengths </u>

electric charge due to a single glass rod in the question ( E ) = $\frac{Q}{2\pi e_{0}rL }$

equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced

applying equation 1 to determine E1

E1 = $\frac{Q}{2\pi e_{0}rL }$ $( \frac{1}{0.01} - \frac{1}{0.03} )$ ( distance from 1 rod is 0.01 m and from the other rod is 0.03 )

= $\frac{11*10^{-9} }{2*3.14*8.85*10^{-12}*0.13 } ( 66.67 )$

= 10.15 * 10^4 N/C

applying equation 1 to determine E2

E2 = $\frac{Q}{2\pi e_{0}rL }$ $( \frac{1}{0.02} - \frac{1}{0.02} )$

therefore E2 = 0

E1 = E3

hence E3 = 10.15*10^4 N/C

4 0

3 years ago