Answer:
2a.) Wavelength = 1.8 m
2b.) F = 66.67 Hz
3a.) Find the attached file
3b.) Wavelength = 0.6 m
Explanation:
Given that the
Length L = 0.9m
Wavelength (λ) = 2L/n
Where n = number of harmonic
If n = 1, then
Wavelength (λ) = 2L = 2 × 0.9 = 1.8 m
b.)
If waves travel at a speed of 120m/s on this string, what is the frequency
associated with the longest wave (first harmonic)?
Given that V = 120 m/s
V = Fλ
But λ = 2L, therefore,
F = V/2L
F = 120/1.8
F = 66.67 Hz
3. b.) If there are two node, the position will be in 3rd position which is 3rd harmonic
Using the same formula,
Wavelength (λ) = 2L/n
Where n = 3
Wavelength (λ) = 2 × 0.9/3
Wavelength (λ) = 0.6 m
Let's choose east as positive x-direction and south as positive y-direction. We can resolve the two displacement along these two axes:
- Displacement 1 (3.5 km,
south of west
![d_{1x}=-(3.5 km)( cos 55^{\circ})=-2.01 km](https://tex.z-dn.net/?f=d_%7B1x%7D%3D-%283.5%20km%29%28%20cos%2055%5E%7B%5Ccirc%7D%29%3D-2.01%20km)
![d_{1y}=(3.5 km)( sin 55^{\circ})=2.87 km](https://tex.z-dn.net/?f=d_%7B1y%7D%3D%283.5%20km%29%28%20sin%2055%5E%7B%5Ccirc%7D%29%3D2.87%20km)
- Displacement 2 (2.7 km,
east of south
![d_{2x}=(2.7 km)( sin 16^{\circ})=0.74 km](https://tex.z-dn.net/?f=d_%7B2x%7D%3D%282.7%20km%29%28%20sin%2016%5E%7B%5Ccirc%7D%29%3D0.74%20km)
![d_{1y}=(2.7 km)( cos 16^{\circ})=2.60 km](https://tex.z-dn.net/?f=d_%7B1y%7D%3D%282.7%20km%29%28%20cos%2016%5E%7B%5Ccirc%7D%29%3D2.60%20km)
So, the total components on the two directions are
![d_x = -2.01 km+0.74 km=-1.27 km](https://tex.z-dn.net/?f=d_x%20%3D%20-2.01%20km%2B0.74%20km%3D-1.27%20km)
![d_y=2.87 km+2.60 km=5.47 km](https://tex.z-dn.net/?f=d_y%3D2.87%20km%2B2.60%20km%3D5.47%20km)
And the magnitude of the hiker's resultant displacement is
![d=\sqrt{(1.27 km)^2+(5.47 km)^2}=5.6 km](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%281.27%20km%29%5E2%2B%285.47%20km%29%5E2%7D%3D5.6%20km)
Answer:
It takes 3 minutes.
Explanation:
The distance between the two subways is 3 miles.
The train travels at an average speed of 60mph (miles per hour).
![\frac{60miles}{1 hour} * \frac{1hour}{60minutes} = \frac{1mile}{1minute}](https://tex.z-dn.net/?f=%5Cfrac%7B60miles%7D%7B1%20hour%7D%20%2A%20%5Cfrac%7B1hour%7D%7B60minutes%7D%20%3D%20%5Cfrac%7B1mile%7D%7B1minute%7D)
We have to convert hours to minutes and we do that by cancelling out the hours and replacing it with minutes.
There are 60 minutes in an hour so we use that, 1 hour/60 minutes and multiply it to the existing speed we have.
The result is 1 mile per minute.
We then multiply the miles by 3 since that is how much we want and we get 3 minutes.
Answer:
<em>Since I can see no choices, I answered it in my own understanding.</em>
Brian - amplitude and frequency
Marcia - amplitude and longitudinal wave
Explanation:
"Sound" and "sound waves" are essential part of a person's life. They can be used for<u> communicating</u> and <u>detecting some object</u>s.
Brian loves singing in the shower which means that he is using a greater amplitude. Amplitude refers to the<em> intensity of the sound </em>or the amount of energy that a sound carries. When one sings in the shower, the sound cannot travel very far. It bounces immediately back to the person singing thus, making the sound bigger. Brian is also using a <em>different range of </em><em>frequency</em><em> compared to his normal way of talking.</em> The frequency of a normal male voice is normally 85 to 180 Hz. A person singing may have a frequency as high as 1,500 Hz.
Marcia talks loudly on the phone. This means that she is also using a greater amplitude because the intensity of her voice is big. Since she is using the telephone, this means that her voice travels in a longitudinal wave through the telephone. This allows her voice to reach to the person on the other end of the line.