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sukhopar [10]
3 years ago
10

PLEASE HELP The Hertzsprung-Russell diagram shown here suggests that the stars with BOTH the highest temperature AND greatest ab

solute
magnitude are

A) giants
B)Super giants
C) White dwarfs
D) stars similar to the sun ​

Physics
1 answer:
uranmaximum [27]3 years ago
8 0

Answer:

White dwarfs because you look at where the highest temperature is and where is the highest magnitude. Fun fact, the sun will become a white dwarf.

Explanation:

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The law of universal gravitation offers a mathematical explanation for the attraction between the moon and Earth.
grandymaker [24]

Answer:

True.

Explanation:

The given statement is true that the law of universal gravitation offers a mathematical explanation for the attraction between the moon and Earth.

According to this law, the forces between two masses can be calculated by the product of their masses and divided by the square of the distance between them. Mathematically, it can be written as :

F=\dfrac{Gm_1m_2}{r^2}

G is universal gravitational constant

Hence, the given statement is true.

5 0
3 years ago
A chemical property is a change in _____. A density B composition of matter C hardness D physical state
NemiM [27]
Composition of matter
5 0
3 years ago
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Rutherford discovered the nucleus of the atom by firing a particles at gold foil. An a particle has a charge of q = +2e and a ma
Readme [11.4K]

Answer:r_0=3.037\times 10^{-14}m

Explanation:

Given

charge on alpha particle=+2e

mass of alpha particle=6.64\times 10^{-27} kg

Charge on gold nucleus=+79e

Velocity at r=1m is 1.9\times 10^{7}

Using Energy conservation

Kinetic energy of particle will be converting to Potential energy as it approaches to nucleus

therefore

\frac{1}{2}mv^2+U_{r=1m}=U_{closest\ to\ nucleus}

\frac{1}{2}\left ( 6.64\times 10^{-27}\right )\left ( 1.9\times 10^{7}^2\right )+\frac{K\left ( 2e\right )\left ( 79e\right )}{1}=\frac{K\left ( 2e\right )\left ( 79e\right )}{r_0}

\frac{1}{2}\left ( 6.64\times 10^{-27}\right )\left ( 1.9\times 10^{7}^2\right )=\frac{9\times 10^9\times 158\times \left ( 1.6\times 10^{-19}\right )}{y}\left [\frac{1}{r_0}-\frac{1}{1}\right ]

on solving we get

\frac{1}{r_0}=3.292\times 10^{13}

r_0=3.037\times 10^{-14}m

8 0
3 years ago
The blades of a fan running at low speed turn at 26.2 rad/s. When the fan is switched to high speed, the rotation rate increases
Lady bird [3.3K]

Answer: 1.79\ rad/s^2

Explanation:

Given

Initial angular speed is \omega_1=26.2\ rad/s

Final angular speed is \omega_2=36.5\ rad/s

Time period t=5.75\ s

Magnitude of the fan's acceleration is given by

\Rightarrow \alpha=\dfrac{\omega_2-\omega_1}{t}

Insert the values

\Rightarrow \alpha=\dfrac{36.5-26.2}{5.75}\\\\\Rightarrow \alpha=\dfrac{10.3}{5.75}\\\\\Rightarrow \alpha=1.79\ rad/s^2

Thus, fan angular acceleration is 1.79\ rad/s^2

8 0
3 years ago
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A car is on cruise control at v=30m/s. If the wind resistance is equal to. F=0.42v² what energy will the car expend to drive 1km
weeeeeb [17]

Answer:

D)378kJ

Explanation:

Applying,

E = F×d................ Equation 1

Where E = Energy expanded by the car, F = Wind resistance, d = distance

From the question,

F = 0.42v²............ Equation 2

Susbtitute equation 2 into equation 1

E = 0.42v²d.............. Equation 3

Given: v = 30 m/s, d = 1 km = 1000 m

Substitute these values into equation 3

E = 0.42(30²)(1000)

E = 378000

E = 378 kJ

Hence the right option is D)378kJ

6 0
3 years ago
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