First of all, we compute the points of interest, i.e. the points where the curve cuts the x axis: since the expression is already factored, we have
Which means that the roots are
Next, we can expand the function definition:
In this form, it is much easier to compute the derivative:
If we evaluate the derivative in the points of interest, we have
This means that we are looking for the equations of three lines, of which we know a point and the slope. The equation
is what we need. The three lines are:
This is the tangent at x = -2
This is the tangent at x = 0
This is the tangent at x = 1
Answer:
more than 1100
Step-by-step explanation:
The contribution margin for each package sold is ...
$6.50 -3.00 = $3.50
The number of packages that must be sold to cover fixed costs is ...
3.50n > 3850
n > 1100 . . . . . . . divide by 3.50
The company will generate a profit if more than 1100 packages are produced and sold each week.
_____
<em>Additional comment</em>
If exactly 1100 packages are sold, then costs are covered, but profit is 0. In order for profit to be positive, more than 1100 packages must be sold.
Answer:
D is the correct answer.
Step-by-step explanation:
Find the portion of the graph that is above the x-axis.
All squares are equal sides.Let X be the side of a square.
Area of square,A = x^2
Here a tile is a square of side length 'x'. The following polynomial represents,
(x - 4) represents "the width of the new tile" (because 4 inches cut from the tile)
4x represents "the area removed from the tile" (since one side of removed tile is 'x' and other is 4 inches.)
x2 represents "area of original tile" of side equal to 'x'
x represents "the length of the new tile" (since length of new tile is not reduced. Length =x and breadth is x-4
Answer:
The Alans's average for the course is 84.5
Step-by-step explanation:
We are given
There are 4 tests, A Term paper and a Final examination.
Score = 92, 78, 82, 90.
Term paper score = 80
Final examination score = 86
Weighted mean = ∑ w.f/∑w
also the sum of all the weights is 100% = 1
weighted mean = 15%*92 + 15%*78+15%*82+15%*90+20%*80+20%*86/1
= 51.3 + 33.2
= 84.5
Therefore the Alans's average for the course is 84.5
