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Ira Lisetskai [31]
3 years ago
12

What is the GCF and LCM for 15,55,52

Mathematics
2 answers:
schepotkina [342]3 years ago
5 0

Answer and Step-by-step explanation:

\huge\boxed{~LCM=8580~}

→ Prime factorization of the numbers for LCM :

15=3*5

55=5*11

52=2*2*13

→ LCM of 15, 55, 52

=2*2*3*5*11*13

=8580

\huge\boxed{~GFC=1~}

→ Prime factorization of the numbers: for GCF

15=3*5

55=5*11

52=2*2*13

→ GCF of 15, 55, 52

=1

LCM = 8580

GCF = 1

jonny [76]3 years ago
3 0

Answer:

LCM = 8580

GCF = 1

Step-by-step explanation:

15 = 3 × 5

55 = 5 × 11

52 = 2 × 2 × 13

LCM(15, 55, 52)

= 2 × 2 × 3 × 5 × 11 × 13

= 8580

---------------------------------------------------

GCF  explanation

The factors of 15 are: 1, 3, 5, 15

The factors of 52 are: 1, 2, 4, 13, 26, 52

The factors of 55 are: 1, 5, 11, 55

Then the greatest common factor is 1.

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It looks like the given equation is

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Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

which lets us rewrite the equation as

sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)

Move everything over to one side and factorize:

sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0

sin(2x) - 3 sin(2x) cos(2x) = 0

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Then we have two families of solutions,

sin(2x) = 0   or   1 - 3 cos(2x) = 0

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[2x = arcsin(0) + 2nπ   or   2x = π - arcsin(0) + 2nπ]

… … …   or   [2x = arccos(1/3) + 2nπ   or   2x = -arccos(1/3) + 2nπ]

(where n is any integer)

[2x = 2nπ   or   2x = π + 2nπ]

… … …   or   [2x = arccos(1/3) + 2nπ   or   2x = -arccos(1/3) + 2nπ]

[x = nπ   or   x = π/2 + nπ]

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7 0
3 years ago
Question 9 of 10
Nonamiya [84]
The answer is B. 0.02
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F(x) = √(3 - x)<br>f(-1) =<br><br>A) 1<br><br>B) 2<br><br>C) undefined<br><br>D) √2
mixas84 [53]

Answer:

B

Step-by-step explanation:

To find the value of f(x) at x=-1, we substitute x=-1 and simplify.

f(-1)=\sqrt{3-(-1)}=\sqrt{3+1)} =\sqrt{4}  =2

f(-1)=2.

Answer B.

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3 years ago
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denpristay [2]

Answer:

Step-by-step explanation:

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If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No
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a.

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