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3 years ago

Six friends attend a party. They form pairs for a game. How many different pairs are possible?

1 answer:

5 0

Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:

1. ABC against DEF

2. ABD against CEF

3. ABE against CDF

4. ABF against CDE

5. ACD against BFE

6. ACE against BDF

7. ACF against BDE

8. ADE against BCF

9. ADF against BCE

10. AEF against BCD

I believe there are 12 combinations... I just can't think of the last 2 though.

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Donovan was playing a basketball shooting game in the arcade. He made 15 shots and missed 25 shots. What is the percentage of sh

Firlakuza [10]

Answer:

Step-by-step explanation:

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3 years ago

Three years ago, Claire borrowed money from her father to pay for a class trip. She agreed to pay 6% simple annual interest on t

Nadya [2.5K]

Answer:

Claire borrowed $500 from her father.

Step-by-step explanation:

Interest = $90

p = ?

r = 6% or 0.06

t = 3

Simple interest formula is :

$I=p\times r\times t$

Putting values in formula we get;

$90=p\times0.06\times3$

$90=0.18p$

p = $500

Hence, Claire borrowed $500 from her father.

3 0

3 years ago

Read 2 more answers

Ble.<br> 6<br> co<br> 10<br> square units

Vlada [557]

Answer:

1/2×10×6=30

Step-by-step explanation:

H=6

L=10

therefore;

1/2×6×10=30

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3 years ago

Read 2 more answers

Do these two expressions represent equivalent expressions? Explain why or why not. 36 + 20 4(9 + 5)

Keith_Richards [23]

Answer:

they are equivalent

Step-by-step explanation:

because 4 times 9 is 36 and 4 times 5 is 20 so it is equal to 36+20

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3 years ago

Read 2 more answers

In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the

Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

$(AB)^2=(BC)^2+(AC)^2$

$(13)^2=(BC)^2+(5)^2$

$169=(BC)^2+25$

$BC=12$

$\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}$

$\sin A=\frac{BC}{AB}$

$A=\sin ^{-1}\frac{12}{13}$

$A=67.38$

Bisector divides the angle in two equal parts, therefore,

$A'=\frac{67.38}{2} =33.69$

In triangle ACD.

$\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}$

$\cos A'=\frac{AC}{AD}$

$\cos (33.69^{\circ})=\frac{5}{AD}$

$0.832=\frac{5}{AD}$

$AD=\frac{5}{0.832} =6.009\approx 6.01$

Therefore the length of the angle bisector of angle ∠A is 6.01.

4 0

3 years ago