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maks197457 [2]
2 years ago
14

Six friends attend a party. They form pairs for a game. How many different pairs are possible?

Mathematics
1 answer:
Leona [35]2 years ago
5 0

Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:

1. ABC against DEF

2. ABD against CEF

3. ABE against CDF

4. ABF against CDE

5. ACD against BFE

6. ACE against BDF

7. ACF against BDE

8. ADE against BCF

9. ADF against BCE

10. AEF against BCD

I believe there are 12 combinations... I just can't think of the last 2 though.

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Joe's summer camp had 81 attendees when it first opened and has grown by 92 attendees per year since then.
pychu [463]

Answer:

A = 92y + 81

Step-by-step explanation:

Because A = number of attendees and if it adds 92 each year, you times the number of years by 92 and add 81 for the ones that were already there

4 0
3 years ago
Brainliest. follow anything . box of chocolates contains seven milk chocolates and six dark chocolates. Five of the milk chocola
Olenka [21]

Answer:

8/13

Step-by-step explanation:

has the slightly lower numbers meaning 11/13 would be milk chocolate with peanuts, and 8/13 would be the dark chocolate

6 0
3 years ago
Read 2 more answers
CAN SOMEONE HELP WITH THIS ASAP!!!
jek_recluse [69]

Answer: x=8

Step-by-step explanation:

Since we are given that ∠ABC and ∠DBC are complementary angles, we know that adding them together should give us 90°. We can use this to solve for x.

6x+13+4x-3=90         [combine like terms]

10x+10=90                 [subtract both sides by 10]

10x=80                       [divide both sides by 10]

x=8

Now, we know that x=8.

6 0
3 years ago
How to do this question plz answer ​
harina [27]

9514 1404 393

Answer:

  300

Step-by-step explanation:

There are 25 ways to select the first student. After that student is removed from the selection pool for the second student, there are 24 ways to select the second student. This gives 25·24 = 600 ways to select 2 students <em>in a particular order</em>.

Since we don't care about the order, we can divide this number by the number of ways two students can be ordered: AB or BA, 2 ways.

  600/2 = 300

There are 300 ways to pick a combination of two students from 25.

__

<em>Additional comments</em>

This sort of selection (2 out of 25) has a formula for it, and an abbreviation for the formula.

 "n choose k" can be written nCk or C(n, k)

The function is a ratio of factorials:

  nCk = n!/(k!(n-k)!)

If you can typeset this, it is written ...

  \displaystyle\binom{n}{k}=\frac{n!}{k!\cdot(n-k)!}

This is different from the formula for the number of <em>permutations</em> of n things taken k at a time. That would be written nPk or P(n, k) = n!/(n-k)!.

5 0
2 years ago
Read 2 more answers
What is a time in the past that you celebrated something good that happened? its for my english class, and i dont know what do w
lapo4ka [179]

Answer:

Easter, Christmas, birthdays, and New Year

Step-by-step explanation:

For me, I would choose Easter because before easter we always go to a church and stay there whole night. After 3-4 a.m, we go home and take a nap. But the most fun activity that we do during Easter is playing a game where we pick the best eggs and beat with each other. Later, our parents hide eggs and a couple of toys in the park and me and my siblings begin finding them.

3 0
3 years ago
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