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maks197457 [2]
3 years ago
14

Six friends attend a party. They form pairs for a game. How many different pairs are possible?

Mathematics
1 answer:
Leona [35]3 years ago
5 0

Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:

1. ABC against DEF

2. ABD against CEF

3. ABE against CDF

4. ABF against CDE

5. ACD against BFE

6. ACE against BDF

7. ACF against BDE

8. ADE against BCF

9. ADF against BCE

10. AEF against BCD

I believe there are 12 combinations... I just can't think of the last 2 though.

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Answer: 18.45\ kg or 18\frac{9}{20}\ kg

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11\frac{1}{2}\ kg=(11+0.5)\ kg=11.5\ kg\\\\1\frac{1}{4}\ kg=(1+0.25)\ kg=1.25\ kg

Since they cleaned up 8.2 kilograms of trash in one neighborhood and 11.5 kilograms in another neighborhood, the total trash they cleaned up was:

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Then:

19.7\ kg-1.25\ kg=18.45\ kg or 18\frac{9}{20}\ kg

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