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2 years ago

Six friends attend a party. They form pairs for a game. How many different pairs are possible?

1 answer:

5 0

Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:

1. ABC against DEF

2. ABD against CEF

3. ABE against CDF

4. ABF against CDE

5. ACD against BFE

6. ACE against BDF

7. ACF against BDE

8. ADE against BCF

9. ADF against BCE

10. AEF against BCD

I believe there are 12 combinations... I just can't think of the last 2 though.

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How is the numeral 55.12 written in words?

Ivan

Fifty-five and twelve hundreths

4 0

3 years ago

Read 2 more answers

Solve for b. 2/3 b + 5 = 20 - b

Arisa [49]

Answer:

b = 9

Step-by-step explanation:

Step 1: Add <em>b</em> on both sides (Addition Equality)

5/3b + 5 = 20

Step 2: Subtract 5 on both sides (Subtraction Equality)

5/3b = 15

Step 3: Divide both sides by 5/3 (Division Equality)

b = 9

6 0

2 years ago

55 POINTS!!!!!!

vladimir1956 [14]

A
c
d
b
c
a
hope it helped!

5 0

3 years ago

V(x + 9)2 = + 25<br> If x + 9 = 5, then x =<br> If x + 9 = -5, then x =

ipn [44]

Answer:

x = -4, v = 2.5

x = -14, v = -2.5

Step-by-step explanation:

I am a bit confused with the beginning part of the question. From what I understand, you are trying to solve for x and then plug x into the top equation to find the value for V. I am sorry if that is not what you are looking for. If it is, look below!

x + 9 = 5

x = 5 -9

x = -4

v(x + 9)2 = 25

v(-4 + 9)2 = 25

v(5)2 = 25

v(10) = 25

v = 25/10

v = 2.5

x + 9 = -5

x = -5 -9

x = -14

v(x + 9)2 = 25

v(-14 + 9)2 = 25

v(-5)2 = 25

v(-10) = 25

v = 25/(-10)

v = -2.5

I hope this helped! If not, I am sorry. :(

4 0

2 years ago

If a values is to the left it is...

Marina CMI [18]

Answer:

Step-by-step explanation:

what?

5 0

2 years ago