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maks197457 [2]
3 years ago
14

Six friends attend a party. They form pairs for a game. How many different pairs are possible?

Mathematics
1 answer:
Leona [35]3 years ago
5 0

Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:

1. ABC against DEF

2. ABD against CEF

3. ABE against CDF

4. ABF against CDE

5. ACD against BFE

6. ACE against BDF

7. ACF against BDE

8. ADE against BCF

9. ADF against BCE

10. AEF against BCD

I believe there are 12 combinations... I just can't think of the last 2 though.

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The value of computer decreases with its age until it is worth nothing a computer that was purchases new for 0 years is worth 22
Georgia [21]

Answer:

V(x) = -\frac{340}{3}x +2220

V(8) = 1313.3

Step-by-step explanation:

Given

Let x represent years and V represents the value.

So, we have:

(x_1,v_1) = (0,2220)

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Solving (a): The linear function

First, we calculate the slope (m)

m = \frac{v_2 - v_1}{x_2 - x_1}

This gives:

m = \frac{1540-2220}{6-0}

m = \frac{-680}{6}

m = -\frac{340}{3}

The linear function is calculated using:

v - v_2 = m(x - x_2)

Where:

(x_2,v_2) = (6,1540)

m = -\frac{340}{3}

So, we have:

v - 1540 = -\frac{340}{3}(x - 6)

Open bracket

v - 1540 = -\frac{340}{3}x +\frac{340}{3}* 6

v - 1540 = -\frac{340}{3}x +680

Make v the subject

v = -\frac{340}{3}x +680+1540

v = -\frac{340}{3}x +2220

So, the function is:

V(x) = -\frac{340}{3}x +2220

Solving (b): When x = 8

Substitute 8 for x in V(x) = -\frac{340}{3}x +2220

V(8) = -\frac{340}{3}*8 +2220

V(8) = -\frac{340*8}{3} +2220

V(8) = -\frac{2720}{3} +2220

Take LCM

V(8) = \frac{-2720+2220*3}{3}

V(8) = \frac{-2720+6660}{3}

V(8) = \frac{3940}{3}

V(8) = 1313.3

<em>Hence, its value after 8 years is 1313.3</em>

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