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Tems11 [23]
2 years ago
14

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

x endfraction minus startfraction x 1 over x squared minus 9 endfraction startfraction (x 5) (x 2) over x cubed minus 9 x endfraction startfraction (x 5) (x 4) over x cubed minus 9 x endfraction startfraction negative 2 x 11 over x cubed minus 12 x minus 9 endfraction startfraction 3 (x 2) over x squared minus 3 x endfraction
Mathematics
1 answer:
weeeeeb [17]2 years ago
6 0

The difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

<h3>How to determine the difference?</h3>

The expression is given as:

\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}

Factor the denominators of the expressions:

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}

Apply the difference of two squares to x² - 9

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}

Take LCM

\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Hence, the difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Read more about expressions at:

brainly.com/question/723406

#SPJ4

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Answer:

2

Step-by-step explanation:

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Veronika [31]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Answer:

mean is equal to 5.12

Step-by-step explanation:

<em>We are given that 32% of college students work fulltime. We have to find the mean for the number of student s who are working full time in a sample of 16</em>

success rate, p = 32% = 0.32

Sample size is denoted as n = 16

The forumla of mean is given as

mean = sample size × success rate

mean = n × p

         = 16 × 0.32

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