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Tems11 [23]
2 years ago
14

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

x endfraction minus startfraction x 1 over x squared minus 9 endfraction startfraction (x 5) (x 2) over x cubed minus 9 x endfraction startfraction (x 5) (x 4) over x cubed minus 9 x endfraction startfraction negative 2 x 11 over x cubed minus 12 x minus 9 endfraction startfraction 3 (x 2) over x squared minus 3 x endfraction
Mathematics
1 answer:
weeeeeb [17]2 years ago
6 0

The difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

<h3>How to determine the difference?</h3>

The expression is given as:

\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}

Factor the denominators of the expressions:

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}

Apply the difference of two squares to x² - 9

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}

Take LCM

\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Hence, the difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Read more about expressions at:

brainly.com/question/723406

#SPJ4

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A box has five items, three good and two defective. three items are selected at random without replacement. let x be the number
user100 [1]
This problem can be solved from first principles, case by case.  However, it can be solved systematically using the hypergeometric distribution, based on the characteristics of the problem:
- known number of defective and non-defective items.
- no replacement
- known number of items selected.

Let
a=number of defective items selected
A=total number of defective items
b=number of non-defective items selected
B=total number of non-defective items
Then 
P(a,b)=C(A,a)C(B,b)/C(A+B,a+b)
where 
C(n,r)=combination of r items selected from n,
A+B=total number of items
a+b=number of items selected

Given:
A=2
B=3
a+b=3
PMF:
P(0,3)=C(2,0)C(3,3)/C(5,3)=1*1/10=1/10
P(1,2)=C(2,1)C(3,2)/C(5,3)=2*3/10=6/10
P(2,0)=C(2,2)C(3,1)/C(5,3)=1*3/10=3/10
Check: (1+6+3)/10=1 ok
note: there are only two defectives, so the possible values of x are {0,1,2}

Therefore the 
PMF:
{(0, 0.1),(1, 0.6),(2, 0.3)}

7 0
3 years ago
Perpendicular to x=1 and passing through (7,11)
Igoryamba
<h3><u>Question:</u></h3>

Find the equation of line perpendicular to x = 1 and passing through (7, 11)

<h3><u>Answer:</u></h3>

The equation of line Perpendicular to x = 1 and passing through (7, 11) is y = 11

<h3><u>Solution:</u></h3>

Given that line is perpendicular to x = 1 and passing through (7, 11)

We have to find the equation of line

The equation of the line in standard form is x = 1

This is a vertical line, so the perpendicular line will be a horizontal line of the form y = b

Since we are given that the line should pass through the point (7, 11) then the equation of the line is y = 11

7 0
3 years ago
Noe take 5 minutes to rides his to down the hill to school and 10 minutes to rides up the hill from school Monday though Friday.
Sophie [7]
5x5=25 + 5x10=50

50+25=75

75x2=150 minutes
7 0
3 years ago
What is the slope of the line on the graph?
raketka [301]

Answer: -6/2 = -3

Step-by-step explanation:

You pick 2 points and then use rise/run=y/x

Because its slanted down its negative

6 0
2 years ago
Evaluate the expression when x = 2.5 and y = 6.<br> 5xy
mamaluj [8]

Answer:

75

Step-by-step explanation:

5(2.5)(6)

5*2.5*6

=75

8 0
2 years ago
Read 2 more answers
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