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3 years ago

Katarina bought a package of 600 stickers. Each sheet in the package has 30 stickers, 25% of the stickers on each

Mathematics

1 answer:

tatuchka [14]3 years ago

5 0

Answer:

answer is b I think

Step-by-step explanation:

because it is

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Graph F(x)=32x+2. Please

olga2289 [7]

Answer:

The required graph is shown below:

Step-by-step explanation:

Consider the provided graph $f(x)=32x+2$

The above function is a linear function.

We can draw the graph of the linear function with the help of two points.

Substitute x = 0 in $f(x)=32x+2$

$f(0)=32(0)+2$

$f(0)=2$

Hence, the coordinates are (0,2)

Substitute f(x) = 0 in $f(x)=32x+2$

$0=32x+2$

$32x=-2$

$x=-0.0625$

Hence, the coordinates are (-0.0625,0)

Now join the above points.

The required graph is shown below:

5 0

3 years ago

Read 2 more answers

Identify the slope in -4x+3y=26

Strike441 [17]

-4 is the slope in the equation

3 0

3 years ago

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What is the GCF of 8,12,16

skad [1K]

Answer:

Step-by-step explanation:

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3 years ago

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Luella has a pond in her yard. She wants to surround it with 330 feet of fencing. Fencing is sold by the yard. How many yards sh

s344n2d4d5 [400]

Answer:

110 yards

330/ 3 ,=110

1yard =3 feet

Step-by-step explanation:

if you multiply 3 to 110=330

or 330 divided by 3=110 yards.

4 0

3 years ago

A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday�s mail. In actuali

Softa [21]

Answer:

P(Y = 0) = 0.09

P(Y = 1) = 0.4

P(Y = 2) = 0.32

P(Y = 3) = 0.19

Step-by-step explanation:

Let the events be:

$W =$ Wednesday

$T =$ Thursday

$F =$ Friday

$S =$ Saturday

Their corresponding probabilities are

$P(W) = 0.3\\P(T) = 0.4\\P(F) = 0.2\\P(S) = 0.1$

Since $Y$ = number of days beyond Wednesday that it takes for both magazines to arrive(so possible $Y$ values are 0, 1, 2 or 3)

The possible number of outcomes are therefore $4^2 = 16\\(W, W), (W, T), (W, F), (W, S)\\(T, W), (T, T), (T, F), (T, S)\\(F, W), (F, T), (F, F), (F, S)\\(S, W), (S, T), (S, F), (S, S)$

The values associated for each of the outcomes are as follows:

$Y(W, W) = 0, Y(W, T) = 1, Y(W, F) = 2, Y(W, S) = 3\\Y(T, W) = 1, Y(T, T) = 1, Y(T, F) = 2, Y(T, S) = 3\\Y(F, W) = 2, Y(F, T) = 2, Y(F, F) = 2, Y(F, S) = 3\\Y(S, W) = 3, Y(S, T) = 3, Y(S, F) = 3, Y(S, S) = 3$

The probability mass function of $Y$ is,

$P(Y = 0) = 0.3(0.3) = 0.09\\P(Y = 1) = P[(W, T) or (T, W) or (T, T)]\\= [0.3(0.4) + 0.3(0.4) + 0.4(0.4)]\\= 0.4\\\\P(Y = 2) = P[(W, F) or (T, F) or (F, W) or (F, T) or (F, F)]\\= [0.3(0.2) + 0.4(0.2) + 0.2(0.3) + 0.2(0.4) + 0.2(0.2)]\\= 0.32\\\\P(Y = 3) = P[(W, S) or (T, S) or (F, S) or (S, W) or (S, T) or (S, F) or (S, S)]\\= [0.3(0.1) + 0.4(0.1) + 0.2(0.1) + 0.1(0.3) 0.1(0.4) + 0.1(0.2) + 0.1(0.1)]\\= 0.19$

7 0

3 years ago