Answer: Your question does not make sense
Explanation:
Answer:
The answer is E) 6.7m at an angle 63° north of east
Explanation:
We begin by writing out our given vectors A,B and C in their respective rectangular Cartesian coordinate form. which are given as A=8i, B=6j and C= -5j (negative because it points towards west which is towards the left which is taken as the negative direction).Now we simply add all three to obtain our final vector given by,

In the last step we just added the like components. Now we will have to calculate the magnitude and angle of V(with respect of the east direction), which is given by,

the angle alpha is always calculated with respect to the horizontal positive axis, and since both components of the vector are positive the vector lies in the first quadrant. Hence the 63° angle north of east is justified. The term north of east means the angle formed in moving from east towards the north that is from the positive horizontal axis to the positive vertical axis.
F= a*m
F= 0.5 kg * 52m/s^2
F=26kgm/s^2 or 26N

Diameter of objective lens = 1.22m
Wavelength of light = 4000Å
We have to find resolving power of telescope ..
★ Resolving power of telescope is given by
RP = D/1.22λ
- D denotes diameter of lens
- λ denotes wavelength of light
RP = D/1.22λ
RP = (1.22×10⁷)/(1.22×4)
RP = 0.25 × 10⁷
RP = 2.5 × 10⁶
★ Resolving power of microscope is given by
RP = 2μsinθ/λ