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Luba_88 [7]
2 years ago
15

A 1200 kg car is travelling qt 20m\s determine the work that must be done on the car by the frictional force of the brakes to st

op the car
Physics
1 answer:
Anestetic [448]2 years ago
4 0

Answer:

240000 Joules

Explanation:

Applying,

The work that must be done by the frictional force of the brake to stop the car must be equal to the kinetic energy of the car.

W = mv²/2.................. Equation 1

Where W = work done by the frictional force of the brake, m = mass of the car, v = velocity of the car.

From the question,

Given: m = 1200 kg, v = 20 m/s

Substitute these values into equation 1

W = (1200×20²)/2

W = 240000 Joules

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Light rays in a material with index of refrection 1.35 1.35 can undergo total internal reflection when they strike the interface
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Answer:

1.30

Explanation:

To calculate the critical angle we have ti use the formula:

sin\theta_c=\frac{n_2}{n_1}

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By taking n_2 and replacing we obtain:

n_2=n_1sin\theta_c=(1.35)sin75.1\°=1.30

hope this helps!!

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3 years ago
Darlene jumps into a swimming pool. She is creating _____. deep water waves impact waves surface currents tidal waves
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3 years ago
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A block has a volume of 0.09 m3 and a density of 4,000 kg/m3. What's the force of gravity acting on the
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2 years ago
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Answer:0.25 times

Explanation:

Given

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7 0
3 years ago
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