A 1200 kg car is travelling qt 20m\s determine the work that must be done on the car by the frictional force of the brakes to st
1 answer:
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Answer:
F=8.0*10^{-10}N
Explanation:
See the attached file for the masses distributions
The force between two masses at distance r is expressed as
since the masses are of the same value, the above formula can be reduce to
using vector notation,Let use consider the force on the lower left corner of the mass due to the upper left side of the mass is
The force on the lower left corner of the mass due to the lower right side of the mass is
The force on the lower left corner of the mass due to the upper right side of the mass is
The net force can be express as
if we insert values we arrive at
if we solve for the magnitude, we arrive at
Hence the net force on one of the masses is
Answer:
v = 1.224 m/s
Explanation:
given,
distance between the two successive maxima = 1.70 m
number of crest = 8
time = 11 s
frequency is equal to number of cycle per secod
velocity of wave
v = f x λ
v = 0.72 x 1.70
v = 1.224 m/s
Hence, the wave speed is equal to v = 1.224 m/s