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Luba_88 [7]
2 years ago
15

A 1200 kg car is travelling qt 20m\s determine the work that must be done on the car by the frictional force of the brakes to st

op the car
Physics
1 answer:
Anestetic [448]2 years ago
4 0

Answer:

240000 Joules

Explanation:

Applying,

The work that must be done by the frictional force of the brake to stop the car must be equal to the kinetic energy of the car.

W = mv²/2.................. Equation 1

Where W = work done by the frictional force of the brake, m = mass of the car, v = velocity of the car.

From the question,

Given: m = 1200 kg, v = 20 m/s

Substitute these values into equation 1

W = (1200×20²)/2

W = 240000 Joules

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Jane starts from her house to take a stroll in her neighborhood. After walking for 2 hours at a steady pace, she has walked 4 mi
9966 [12]

Answer:

C. 2 mph

Explanation:

speed equals total distance covered in total time of of travel

since,

total distance = 4 miles

time taken = 2 hrs

speed = 4m / 2hrs =2mph

3 0
3 years ago
Read 2 more answers
A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t
MrRissso [65]

Answer:

a) T = 608.22 N

b) T = 608.22 N

c) T = 682.62 N

d) T = 533.82 N

Explanation:

Given that the mass of gymnast is m = 62.0 kg

Acceleration due to gravity is g = 9.81 m/s²

Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.

So;

To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;

T = mg

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs the rope at a constant rate tension in the string is

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs up the rope with an upward acceleration of magnitude

a = 1.2 m/s²

the tension in the string is  T - mg = ma (Since acceleration a is upwards)

T = ma + mg

= m (a + g )

= (62.0 kg)(9.81 m/s² + 1.2  m/s²)

= (62.0 kg) (11.01 m/s²)

= 682.62 N

When the gymnast climbs up the rope with an downward acceleration of magnitude

a = 1.2 m/s² the tension in the string is  mg - T = ma (Since acceleration a is downwards)

T = mg - ma

= m (g - a )

= (62.0 kg)(9.81 m/s² - 1.2 m/s²)

= (62.0 kg)(8.61 m/s²)

= 533.82 N

5 0
2 years ago
Explain your results: How can Earth’s gravity affect the water when the water isn’t actually touching the Earth? (2 pts) Do you
Levart [38]

Answer:

Because the Earth has so much gravity, it can hold water, land, and life in it's atmosphere.

(Not sure what beaker you are talking about, so sorry) But I don't think the moon's gravity would have an effect on a beaker of water because the Earth's gravity is much more than the moon's.

I think you would be able to feel a little bit of Earth's gravity  on the moon because the Earth's gravity pulled the moon into orbit, therefore, gravity on Earth my have some effect on the moon.

hope this helps!

5 0
3 years ago
What are the contour lines on a contour map?
dalvyx [7]
Contour lines are lines that signifies the elevation on a mountain or hill
5 0
2 years ago
Read 2 more answers
"An object weighing 10.01 grams is placed in a graduated cylinder containing 3.90 mL of water. If the total volume of the object
Alex73 [517]

Answer:

Density of the object = 1.9399g/mL

Explanation:

Mass of object = 10.01g

Volume of water = 3.90mL

Volume of Object + Water = 9.06mL

Therefore, volume of Object = Volume of Object + Water - Volume of Water

= 9.06mL - 3.90mL

= 5.16mL

Density by definition is the mass per unit volume of a substance.

Density of the object = mass/volume

= 10.01/5.16

= 1.9399g/mL or 1.94kg/m3

8 0
3 years ago
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