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Elanso [62]
3 years ago
14

three times a number is three more than twice the number which equation can be used to find the value of X the unknown number

Mathematics
2 answers:
Leno4ka [110]3 years ago
8 0

Answer:

3x = 2x + 3.

Step-by-step explanation:

In the question it has been given that three times a number is three more than twice the number.

Let the number is x.

Then by the given statement 3x = 2x + 3

So equation formed can be used to find the value of x

3x - 2x = 3

x = 3

Therefore, the number is 3 and equation to be solved for x is 3x = 2x + 3.

Lyrx [107]3 years ago
7 0
Let the value of the number be represented as x. 

Then, write out an equation; 

3x=2x+3 <--- Solve for x now 
3x-2x=3 
x=3 

Therefore the number is 3. 

Hope I helped :) 
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Suppose S is between R and T. Use the Segment Addition Postulate to solve for z.. RS=2z+6, ST=4z−3, RT=5z+12
Lynna [10]

Answer:

9

Step-by-step explanation:

If S is between R and T, then RS+ST = RT

Given the following parameters

RS=2z+6,

ST=4z−3,

RT=5z+12

On substituting

2z+6+4z-3 = 5z+12

Collect like terms

2z+4z-5z = 12+3-6

6z-5z = 15-6

z = 9

Hence the value of z is 9

7 0
3 years ago
Daniel bought four bags of potatoes. The weight of the first bag was 2.6 pounds. The second bag weighed 0.4 pound less than twic
ipn [44]

Answer:

Average weight of the bags of potatoes is 3.8 pounds.

Step-by-step explanation:

Given:

Weight of the first bag, W_{1}=2.6 pounds.

Weight of the second bag is 0.4 pounds less than twice the weight of first bag. This means,

W_{2}=2W_{1}-0.4=2(2.6)-0.4=5.2-0.4=4.8\textrm{ pounds}

Weight of the third bag is 0.6 pounds more than that of the first bag. This means,

W_{3}=W_{1}+0.6=2.6+0.6=3.2\textrm{ pounds}

Weight of the fourth bag is 0.3 pounds less than that of the second bag. This means,

W_{4}=W_{2}-0.3=4.8-0.3=4.5\textrm{ pounds}

Therefore, the average weight of the bags of potatoes is given as the sum of all the weights and then divide the sum by 4. Therefore,

W_{average}=\frac{W_{1}+W_{2}+W_{3}+W_{4}}{4}=\frac{2.6+4.8+3.2+4.5}{2}=\frac{15.1}{4}=3.775\approx 3.8

Therefore, average weight of the bags of potatoes is 3.8 pounds.

8 0
3 years ago
Olivia deposit 6952 in a savings account paying 3.72% interest to the nearest dollar how much money does Olivia have in total af
lianna [129]
Pretty sure 11,090!............................
4 0
3 years ago
The world record for the fastest typing speed is 212 words per minute. How many words per second is this? Round to the nearest t
taurus [48]

Answer:

3.5

Step-by-step explanation:

212 words / 60 seconds in a minute = 3.53 repeating


6 0
3 years ago
Read 2 more answers
A randomized trial tested the effectiveness of diets on adults. Among 36 subjects using Diet 1, the mean weight loss after a yea
seropon [69]

Answer:

The 95%  confidence interval is

           0.45 <  \mu_1 - \mu_2  < 5.35

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1   =  36

   The first  sample mean is  \= x_1  =  3.5

   The first standard deviation is  \sigma_1  =  5.9 \ pounds

   The second  sample size is n_2 =  36

    The second  sample mean is  \= x_2 =  0.6

    The second  standard deviation is \sigma  =  4.4

Generally the degree of freedom is mathematically represented as

     df =  \frac{ [ \frac{s_1^2 }{n_1 }  + \frac{s_2^2 }{n_2} ]^2 }{ \frac{1}{(n_1 - 1 )} [ \frac{s_1^2}{n_1} ]^2 + \frac{1}{(n_2 - 1 )} [ \frac{s_2^2}{n_2} ]^2  }

=>  df =  \frac{ [ \frac{5.9^2 }{34 }  + \frac{4.4^2 }{34} ]^2 }{ \frac{1}{(34 - 1 )} [ \frac{5.9^2}{34} ]^2 + \frac{1}{(34- 1 )} [ \frac{4.4^2}{ 34} ]^2  }

=>  df =63

Generally the standard error is mathematically represented as

      SE =  \sqrt{ \frac{s_1 ^2 }{n_1}  + \frac{s_2^2 }{ n_2 } }

=>  SE =  \sqrt{ \frac{ 5.9 ^2 }{ 36 }  + \frac{ 4.4^2 }{36} }

=>  SE = 1.227

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the t distribution table the critical value  of   at a degree of freedom of is  

     t_{\frac{\alpha }{2}, 63  } =  1.998

Generally the margin of error is mathematically represented as

        E =  t_{\frac{\alpha }{2}, 63  } *  SE

=>    E =  1.998 * 1.227

=>    E =  2.45

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 - \x_2) -E <  \mu

 => (3.5  - 0.6) - 2.45 <  \mu_1 - \mu_2  < (  3.5  - 0.6)  + 2.45

=>   0.45 <  \mu_1 - \mu_2  < 5.35

     

8 0
2 years ago
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