A) The mass is an intrinsic property of an object: it means it depends only on the properties of the object, so it does not depend on the location of the object. Therefore, Gary's mass at 300 km above Earth's surface is equal to his mass at the Earth's surface.
b) The weight of an object is given by

where
m is the mass

is the gravitational acceleration at the location of the object, with G being the gravitational constant, M the mass of the planet and r the distance of the object from the center of the planet.
At the Earth's surface,

, so Gary's weight is

(1)
where m is Gary's mass.
Then, we must calculate the value of g at 300 km above Earth's surface. the Earth's radius is

So the distance of Gary from the Earth's center is

The Earth's mass is

, so the gravitational acceleration is

Therefore, Gary's weight at 300 km above Earth's surface is

(2)
If we compare (1) and (2), we find that Gary's weight has changed by

So, Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.
Answer:
From spectral lines astronomers can determine not only the element, but the temperature and density of that element in the star. The spectral line also can tell us about any magnetic field of the star. The width of the line can tell us how fast the material is moving. We can learn about winds in stars from this.
Explanation:
Answer: polar ice reflecting the Sun's light back toward space
The older students should be able to complete the puzzle in a shorter amount of time than the younger students