For this problem, you should be able to differentiate the variables presented from each other in order to substitute them in their corresponding places in the formula or formulas to be utilized in this problem. As for this problem, the only formula to be utilized would be the formula for power which is force multiplied to distance over time or simply have force multiplied to speed since speed is equal to distance over time.
The formula would like this:
Power = force x distance / time Power = force x speed
P = 490 N x 2 m / 10 s P = 490 N x (2 m / 10 s)
P = 980 N m / 10 s P = 490 N x 0.2 m / s
P = 98 W P = 98 W
So the average power required to lift a 490-newton object a vertical distance of 2.0 meters in 10 seconds would be 98 watts.
Answer:
a) distance d = 293.36ft
b) acceleration a = 14.67ft/s^2
Explanation:
Acceleration is the change in velocity per unit time.
a = ∆v/t ....1
Given;
Initial velocity vi = 30mph × 5280ft/mile × 1/3600s/h
vi = 44ft/s
Final velocity vf = 70mph × 5280ft/mile × 1/3600s/h
vf = 102.67ft/s
time = 4.0s
From equation 1, acceleration is;
a = ∆v/t = (102.67-44)/4 = 14.67ft/s^2
Distance travelled can be given as;
d = ut + 0.5at^2 .....2
u = 44ft/s
t = 4
a = 14.67ft/s^2
Substituting into the equation 2
d = 44(4) + 0.5(14.67×4^2)
d = 293.36ft
The answer for this question should be TRUE
Answer:
Explanation:
In this case, law of conservation of energy will be implemented. It states that "the energy of the system remains conserved until or unless some external force act on it. Energy of the system may went through the conversion process like kinetic energy into potential and potential into kinetic energy.But their total always remain the same in conserved systems."
Given data:
Height of tower = 10.0 m
Depth of the pool = 3.00 cm
Mass of person = 61.0 kg
Solution:
Initial energy = Final energy
As the person was at height initially so it has the potential energy only.
Lets find out the magnitude of the force that the water is exerting on the diver.
W =ΔK.E
F = 1992.67 N
Acceleration = (change in speed) / (time for the change)
Change in speed = (ending speed) - (starting speed)
Change in speed = (25 m/s) - (5 m/s) = 20 m/s
Time for the change = 20 sec
Acceleration = (20 m/s) / (20 sec)
<em>Acceleration = 1 m/s²</em>
