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Otrada [13]
2 years ago
7

Magnetic Field: is a region around the charged particle where the electric force is exerted on other charged particles.

Physics
1 answer:
nalin [4]2 years ago
8 0
The answer for this question should be TRUE
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Plz help me with this ^^^
gogolik [260]
Assuming all the landmasses continue to move towards a sort of epicenter, large mountain ranges would appear in Africa and Europe.
6 0
4 years ago
Read 2 more answers
How much energy is transferred by five 60 watt bulb in 20 minutes
Annette [7]

(5 bulbs)·(60 watts/bulb)·(20 minutes)·(1 joule per sec/watt)·(60 sec/minute)

=  (5·60·20·1·60)  (bulb·watt·minute·joule per sec·sec) / (bulb·watt·minute)

=        360,000 joules
_____________________________________________

Another way:

Five 60-watt bulbs  =  300 watts  =  0.3 kilowatt

20 minutes  =  1/3 hour

              (0.3 kilowatt) · (1/3 hour)  =  0.1 kilowatt-hour
8 0
3 years ago
If anyone could answer my question , please help -,- xD
Paraphin [41]
Kinematics is the study of motion, without any reference to the forces that cause the motion. It basically means studying how things are moving, not why they're moving. It includes concepts such as distance or displacement, speed or velocity, and acceleration, and it looks at how those values vary over time.
5 0
3 years ago
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3. If you were in a car collision, would you rather be hit by Vehicle 1 (2,027 kg) or Vehicle 2 (1,415 kg) from Activity 73? Exp
Inga [223]

Answer:

I say vehicle one, because both will apply the same amount of force but, because vehicle two has less mass, it will accelerate more rather than vehicle one which will accelerate less.

5 0
3 years ago
A body start from rest are moves with uniform acceleration of 60m/1/5^2.what distance does it cover in third second?
VladimirAG [237]

Answer:

Let's see what to do buddy...

Explanation:

_________________________________

a =  \frac{60}{ ({ \frac{1}{5}) }^{2} } =  \frac{60}{ \frac{1}{25} } = 60 \times 25 \\  \\ a = 15 \times 4 \times 25 = 15 \times 100 \\ a = 1500 \:  \frac{m}{ {s}^{2} }

_________________________________

The body start from rest which means :

v(0) = 0

_________________________________

In third second means :

t = 2 -----¢ t = 3 -----¢ ∆t = 1

_________________________________

We have this equation to find the distance.

∆x =  \frac{1}{2} \: a \:  {t}^{2}  + v(0) \: t \\

_________________________________

∆x =  \frac{1}{2} \times 1500 \times 1 + 0 \times 1 \\   \\ ∆x = 750 + 0 = 750

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

4 0
3 years ago
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