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Vesnalui [34]
3 years ago
14

You throw a rock upward. The rock is moving upward, but it is slowing down. If we define the ground as the origin, the position

of the rock is _____ and the velocity of the rock is _____.
A. positive, positive
B. positive, negative
C. negative, positive
D. negative, negative
Physics
1 answer:
lyudmila [28]3 years ago
6 0

Answer:

A. Positive, positive

Explanation:

As we defined the ground is the origin, as long as the rock is above the ground, its position would always be positive.

As for velocity, as long as the rock is moving upwards, its direction is also upward, so its velocity is always positive. The velocity will become negative when the rock falls down.

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A lamp hangs vertically from a cord in a descending elevator that decelerates at 1.4 m/s2. (a) If the tension in the cord is 91
yanalaym [24]

Answer:8.125 kg

Explanation:

Given

deceleration of elevator a=1.4\ m/s^2

suppose T is the tension in the cord

therefore net force on lamp is

F_{net}=T-mg

F_{net}=ma

direction of a and g is in the same direction

T-mg=m(1.4)

T=m(g+a)

m=\dfrac{T}{g+a}

m=\dfrac{91}{9.8+1.4}

m=8.125\ kg

6 0
3 years ago
Which of the following is not something that the atmosphere does for us?
Masja [62]
Tha atmosphere has no effect on gravity.
4 0
3 years ago
Read 2 more answers
A man weighing 180 lbf pushes a block weighing 100 lbf along a horizontal plane. the dynamic coefficient of friction between the
Talja [164]
The first thing you should know is that the work is defined as:
 W = F * d
 Where
 F = force
 d = displacement
 We have then
 (a) the block
 F = (0.2) * (100) = 20
 d = 100
 W = (20) * (100) = 2000 ft.lbf
 (b) the man as the system.
 F = (0.2) * (100 + 180) = 56
 d = 100
 W = (56) * (100) = 5600 ft.lbf
 answer:
 (a) 2000 ft.lbf
 (b) 5600 ft.lbf
3 0
3 years ago
If it takes 100 N to move a box 5 meters, what is the work done on the box?
jeyben [28]

Answer:  D.   500 J

=========================================================

Explanation:

To find the amount of work done, we multiply the force by displacement

work = force*displacement

work = (100 N)*(5 m)

work = (100*5) Nm

work = 500 J

In this case, "Nm" refers to "Newton meters" and not "nanometers"

1 newton meter is equal to 1 joule

7 0
2 years ago
uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is th
adoni [48]

Answer:

potential difference V= 300 volts

Explanation:

Given:

d= 2.0 cm = 0.02m

E = 15 kN/C = 15 × 10³ N/C

For a uniform field between two plates, the Electric Filed Intensity (E) is proportional to the potential difference (V) and inversely  proportional to distance between the plates.

E= V/d

⇒ V= E×d = 15 × 10³ N/C × 0.02 m = 300 volts  (∴1 Nm/C = 1 J/C= 1 volts)

7 0
3 years ago
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