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4 years ago

How many atoms are there in 14.3 g of xenon?

Chemistry

1 answer:

olasank [31]4 years ago

8 0

Answer:

6.56 × 10²² atoms Xe

Explanation:

Step 1: Find conversions

Molar Mass Xe - 131.29 g/mol

Avagadro's Number: 6.022 × 10²³

Step 2: Use Dimensional Analysis

$14.3 \hspace{3} g \hspace{3} Xe(\frac{1 \hspace{3} mol \hspace{3} Xe}{131.29 \hspace{3} g \hspace{3} Xe} )(\frac{6.022(10)^{23} \hspace{3} atoms \hspace{3} Xe}{1 \hspace{3} mol \hspace{3} Xe} )$ = 6.55911 × 10²² atoms Xe

Step 3: Simplify

We have 3 sig figs.

6.55911 × 10²² atoms Xe ≈ 6.56 × 10²² atoms Xe

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3 years ago

Which statement correctly describes a reaction in dynamic equilibrium? At dynamic equilibrium, the reactions stop and the amount

harkovskaia [24]

Answer:

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3 years ago

Read 2 more answers

The air pressure for a certain tire is 109 kPa. What is this pressure in atmospheres?

Len [333]

1.08 atm is the pressure for a certain tire in atmosphere.

<u>Explanation:</u>

One kilo pascal (1 kPa) corresponds to 1000 pascal. Another common unit used for pressure is atmosphere (symbolised as ‘atm’). 1 atm refers the standard atmospheric pressures and corresponds to 760 mm Hg and 101.3 kPa. Atmospheric pressures are commonly referred as square inches (psi)/ pounds.

$1 \mathrm{atm}=101.3 \mathrm{kPa}=101,325 \mathrm{Pa}=760 \mathrm{mm} \mathrm{Hg}=760 \text { torr }=14.7 \mathrm{lb} / \mathrm{in}^{2}(\mathrm{psi})$

Given:

The air pressure for a certain tire = 109 kPa

We need to find pressure in atmospheres

So, we know,

1 atm = 101.3 kPa

Hence,

$\frac{109 \mathrm{kPa}}{1} \times \frac{1 \mathrm{atm}}{101.3 \mathrm{kPa}}=1.076=1.08 \mathrm{atm}$

1.08 atm is the pressure for a certain tire in atmosphere.

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3 years ago

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3 years ago