How many atoms are there in 14.3 g of xenon?

Chemistry

1 answer:

olasank [31]3 years ago

8 0

Answer:

6.56 × 10²² atoms Xe

Explanation:

Step 1: Find conversions

Molar Mass Xe - 131.29 g/mol

Avagadro's Number: 6.022 × 10²³

Step 2: Use Dimensional Analysis

$14.3 \hspace{3} g \hspace{3} Xe(\frac{1 \hspace{3} mol \hspace{3} Xe}{131.29 \hspace{3} g \hspace{3} Xe} )(\frac{6.022(10)^{23} \hspace{3} atoms \hspace{3} Xe}{1 \hspace{3} mol \hspace{3} Xe} )$ = 6.55911 × 10²² atoms Xe

Step 3: Simplify

We have 3 sig figs.

6.55911 × 10²² atoms Xe ≈ 6.56 × 10²² atoms Xe

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SIZIF [17.4K]

Answer:

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Explanation:

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3 years ago

Write the net ionic equation for the reaction between hydrochloric acid and potassium cyanide. Do not include states such as (aq

zhannawk [14.2K]

Answer: $H^++CN^-\rightarrow HCN$ , product favoured

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we do not include the spectator ions in the equations.

When hydrochloric acid react with potassium cyanide, then it gives potassium chloride and hydrocyanic acid as products.

The complete ionic equation will be:

$H^++Cl^-+K^++CN^-\rightarrow K^++Cl^-+HCN$