Answer:
Angular momentum is conserved if there are no external forces
P1 = P2
I1 ω1 = I2 ω2
ω2 / ω1 = I1 / I2
If the skater pulls their arms in (I2 < I1) then the angular speed must increase for angular momentum to be conserved.
Answer:
Explanation:
We will use the relationship between impulse and momentum.
We are considering the change of momentum of Superman at the moment of collision.
This force is distributed throughout Kal-El’s chest. So, the average force is
Either A or D. If I were answering I'd go with my git answer and say A
Answer:
F=ma
So we have to find acceleration
V^2-U^2=2as
V=0 ,U=10m/s ,s= 50m
(0)^2-(10)^2=2*50*a
0-100=100*a
-100=100*a
-100/100=a
-1=a
F=ma
F=1000*-1
F= -1000N
Hope this is the right answer
Answer:
c. 1.11 m/s down
Explanation:
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Assuming the balloon and projectile are originally at rest:
(90 kg) (0 m/s) + (10 kg) (0 m/s) = (90 kg) v + (10 kg) (10 m/s)
0 kg m/s = (90 kg) v + 100 kg m/s
v = -1.11 m/s