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Vlad1618 [11]
3 years ago
6

Consider the following standard reduction potentials: Zn2+(aq) + 2 e− LaTeX: \longrightarrow⟶ Zn(s) Eo = −0.76 V Mg2+(aq) + 2 e−

LaTeX: \longrightarrow⟶ Mg(s) Eo = −2.37 V Ag+(aq) + e− LaTeX: \longrightarrow⟶ Ag(s) Eo = +0.80 V Which is the strongest oxidizing agent? Group of answer choices
Chemistry
1 answer:
zavuch27 [327]3 years ago
8 0

<u>Answer:</u> The strongest oxidizing agent is silver.

<u>Explanation:</u>

Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions and reduction reaction is the reaction in which an atom gains electrons.

The substance having highest positive reduction E^o potential will always get reduced and will undergo reduction reaction easily.

We are given:

Zn^{2+}(aq.)+2e^-\rightarrow Zn(s);E^o =-0.76V

Mg^{2+}(aq.)+2e^-\rightarrow Mg(s);E^o =-2.37V

Ag^{+}(aq.)+e^-\rightarrow Ag(s);E^o =+0.80V

As, silver has the highest positive reduction potential. So, it will be the strongest oxidizing agent.

Hence, the strongest oxidizing agent is silver.

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Answer:

Yes

Explanation:

Chemical reactions often involve changes in energy due to the breaking and formation of bonds. Reactions in which energy is released are exothermic reactions, while those that take in heat energy are endothermic.

3 0
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As shown below, a hammer was placed into a graduated cylinder. What is the volume displacement of the hammer?
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Answer:

B. 4 ml

Explanation:

Volume displacement of the hammer = volume volume of water when the hammer was placed into the cylinder - volume of water only before the hammer was placed into the cylinder.

Volume volume of water when the hammer was placed into the cylinder = 69 ml

Volume of water only before the hammer was placed into the cylinder = 65 ml

Volume displacement of the hammer = 69 ml - 65 ml = 4 ml

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7 0
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What is the mole fraction of each component if 3.9 g of benzene (C6H6) is dissolved in 4.6 g of toluene (C7H8)
Savatey [412]

Answer:

Step 1 of 6

(a)

The mass of benzene is  , so calculate the moles of benzene as follows:



The mass of toluene is, so calculate the moles of toluene as follows:



Now, calculate the mole fraction as follows:





Therefore, the mole fraction of benzene and toluene is  and  respectively.

Step 2 of 6

(b)

The formula to calculate the partial pressure is as follows:



Here,  is the partial pressure of benzene,  is the vapour pressure of pure benzene and  is the mole fraction of benzene.

Vapour pressure of pure benzene at  is.

Substitute the values in the equation as follows:



Therefore, the partial pressure is  .

Step 3 of 6

(c)

Vapor pressure of the solution at 1 atm is  .

When the total pressure of the vapour pressure of the mixture is  at a temperature, then, the solution boils. It corresponds to the boiling point of the solution.

Calculate the total pressure of the solution at  as follows:



Since, the total pressure is less than the atmospheric pressure, the solution will not boil at  .

Calculate the total pressure of the solution at  as follows:



Since, the total pressure is greater than the atmospheric pressure, the solution will boil at  .

Therefore, the boiling point of the solution is  .

Step 4 of 6

(d)

Mole fraction of benzene at  is calculated as follows:



Mole fraction of toluene at  is calculated as follows:



Therefore, the mole fractions of benzene and toluene are  and  respectively.

Step 5 of 6

(e)

Vapor pressure of benzene at  is  .

Partial pressure of benzene is calculated as follows:



Vapor pressure of toluene at  is  .

Partial pressure of toluene is calculated as follows:



Step 6 of 6

Weight composition of the vapour that is in equilibrium with the solution is calculated as follows:



Weight composition of the vapour that is in equilibrium with the solution is calculated as follows:



Explanation:

mark me as brainliest

4 0
3 years ago
Read 2 more answers
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