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Maru [420]
3 years ago
13

How many electrons will a non-metal generally have in its outer shell? 1 - 3 1 - 4 4 - 7 8

Chemistry
2 answers:
Andrews [41]3 years ago
8 0

<u>Answer:</u> The correct answer is 4-7.

<u>Explanation:</u>

A non-metal is defined as the element which gains electron to attain stable electronic configuration and to attain a negative ion which is anion.

X+ne^-\rightarrow X^{n-}

Non-metals are the elements which belong to Group 14 to Group 17.

The valence electronic configuration of the elements:

  • Belonging to Group 14 = ns^2np^2

Number of valence electrons = 4

  • Belonging to Group 16= ns^2np^3

Number of valence electrons = 5

  • Belonging to Group 16 = ns^2np^4

Number of valence electrons = 6

  • Belonging to Group 17 = ns^2np^5

Number of valence electrons = 7

Hence, the correct answer is 4-7.

AlladinOne [14]3 years ago
4 0

They generally have 4 - 7 electrons in their outer shell.

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Answer:

Explanation:

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What is indicated by 'A' in the figure below? A. -VE B. +Ea C. -Ea D. +VE
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What is the total number of grams of mg consumed when 0.50 mole of h2 is produced
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Barium sulfate is made by the following reaction.
ipn [44]

Answer:

                      %age Yield =   96 %

Explanation:

                    The balance chemical equation for given double replacement reaction is,

                      Ba(NO₃)₂ + Na₂SO₄ → BaSO₄ + 2 NaNO₃

Step 1: <u>Calculate moles of Ba(NO₃)₂:</u>

Moles  =  Mass / M.Mass

Moles  =  75.1 g / 261.33 g/mol

Moles  =  0.2873 moles of Ba(NO₃)₂

Step 2: <u>Find out moles of BaSO₄ formed:</u>

According to balance chemical equation,

                  1 mole of Ba(NO₃)₂ produced  =  1 mole of BaSO₄

So,

        0.2873 moles of Ba(NO₃)₂ will produce  =  X moles of BaSO₄

Solving for X,

                      X =  0.2873 mol × 1 mol / 1 mol

                       X =  0.2873 moles of BaSO₄

Step 3: Calculate Theoretical Mass of BaSO₄:

Mass  =  Moles × M.Mass

Mass  =  0.2873 mol × 233.38 g/mol

Mass  = 67.07 g of BaSO₄

Step 4: <u>Calculate %age Yield as:</u>

                 Theoretical Yield  =  67.07 g

                  Actual Yield  =  64.4 g

                  %age Yield  =  <u>???</u>

Formula Used:

                   %age Yield  =  (Actual Yield ÷ Theoretical Yield) × 100

Putting Values,

                   %age Yield  =  (64.4 g ÷ 67.07 g) × 100

                   %age Yield =  96.01 % ≈ 96 %

6 0
3 years ago
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