<u>Answer:</u> The value of
is 0.136 and is reactant favored.
<u>Explanation:</u>
Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
For the chemical reaction between carbon monoxide and hydrogen follows the equation:

The expression for the
is given as:
![K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D)
We are given:
![[NH_3]=0.25M](https://tex.z-dn.net/?f=%5BNH_3%5D%3D0.25M)
![[H_2]=0.75M](https://tex.z-dn.net/?f=%5BH_2%5D%3D0.75M)
![[N_2]=1.1M](https://tex.z-dn.net/?f=%5BN_2%5D%3D1.1M)
Putting values in above equation, we get:


There are 3 conditions:
- When
; the reaction is product favored. - When
; the reaction is reactant favored. - When
; the reaction is in equilibrium.
For the given reaction, the value of
is less than 1. Thus, the reaction is reactant favored.
Hence, the value of
is 0.136 and is reactant favored.
Answer:
pH = 12.08
Explanation:
First we <u>calculate how many moles of each substance were added</u>, using <em>the given volume and concentration</em>:
- HBr ⇒ 0.05 M * 75 mL = 3.75 mmol HBr
- KOH ⇒ 0.075 M * 74 mL = 5.55 mmol KOH
As HBr is a strong acid, it dissociates completely into H⁺ and Br⁻ species. Conversely, KOH dissociates completely into OH⁻ and K⁺ species.
As there are more OH⁻ moles than H⁺ moles (5.55 vs 3.75), we <u>calculate how many OH⁻ moles remain after the reaction</u>:
- 5.55 - 3.75 = 1.8 mmoles OH⁻
With that<em> number of moles and the volume of the mixture</em>, we <u>calculate [OH⁻]</u>:
- [OH⁻] = 1.8 mmol / (75 mL + 74 mL) = 0.0121 M
With [OH⁻], we <u>calculate the pOH</u>:
With the pOH, we <u>calculate the pH</u>:
D is correct.
Another equivalent explanation currently used is the watermelon. Thomson believed (if using the watermelon as an example) that the red part, was some kind of positive matter and the seeds where electrons - electrons stuck to a positively charged matter.
Hope it helped,
Happy homework/ study/ exam!