Answer: Please see answers in explanation column
Explanation:
Name Type of sugars
Sucrose Disaccharide
Sucrose, also called table sugar with molecular formulae C12H22O11 is a disaccharide composed of two monosaccharides ( 50%glucose + 50% fructose.).
Lactose Disaccharide
Lactose with molecular formula C12H22O11, found in milk is a disaccharide composed of two monosaccharides (galactose and glucose).
Fructose Monosaccharide
Fructose with molecular formulae C6H12O6 is a natural sugar mostly found in fruits.
Starch Polysaccharide
Starch ,a complex carbohydrate with molecular formula (C6H10O5)n, is a Polysaccharide containing many units of glucose joined together by 1,4 linkages. Sources of starch can be found in the parts of plants( roots, tubers etc).
Glucose monosaccharides
Glucose, is a simple sugar (monosaccharides) with the molecular formula C6H12O6. It is found in parts of plants as well as in humans and known as blood sugar because of its location in the bloodstream.
W = F * s
W = 100 * 10
W = 1000 J
In short, Your Answer would be 1000 Joules
Hope this helps!
Answer:
ΔS = +541.3Jmol⁻¹K⁻¹
Explanation:
Given parameters:
Standard Entropy of Fe₂O₃ = 90Jmol⁻¹K⁻¹
Standard Entropy of C = 5.7Jmol⁻¹K⁻¹
Standard Entropy of Fe = 27.2Jmol⁻¹K⁻¹
Standard Entropy of CO = 198Jmol⁻¹K⁻¹
To find the entropy change of the reaction, we first write a balanced reaction equation:
Fe₂O₃ + 3C → 2Fe + 3CO
To calculate the entropy change of the reaction we simply use the equation below:
ΔS = ∑S
- ∑S
Therefore:
ΔS = [(2x27.2) + (3x198)] - [(90) + (3x5.7)] = 648.4 - 107.1
ΔS = +541.3Jmol⁻¹K⁻¹
