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3 years ago

A tow truck uses a force of 100 N to pull a car 10 meters. How much work was done?

Chemistry

2 answers:

Rainbow [258]3 years ago

8 0

W = F * s
W = 100 * 10
W = 1000 J

In short, Your Answer would be 1000 Joules

Hope this helps!

olga55 [171]3 years ago

7 0

Answer: Work done by the tow truck is 1000 J

Explanation:

Work is defined as the amount of energy that is being transferred in order to move an object by an external force. It is expressed in joules.

The equation used to calculate amount of work done is:

$W=F\times d$

where,

W = Work done = ? J

F = Force applied = 100 N

d = Displacement of the car = 10 m

Putting values in above equation, we get:

$W=100\times 10=1000J$

Hence, work done by the tow truck is 1000 J

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The empirical formula of the oxide is Co₂O₃.

Step 1. Calculate the mass of oxygen

Your reaction is

Cobalt + oxygen ⟶ cobalt oxide

29.05 g + x g ⟶ 40.88 g

According to the Law of Conservation of Mass, the total mass of the reactants must equal the total mass of the products. Thus,

29.05 g + x g ⟶ 40.88 g

x = 40.88 – 29.05 = 11.83

Step 2. Calculate the moles of each element

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Co to O.

Moles of Co = 29.05 g Co × (1 mol Co /(58.93 g Co) = 0.492 96 mol Co

Moles of O = 11.83 g O × (1 mol O/16.00 g O) = 0.739 38 mol O

Step 3. Calculate the molar ratio of the elements

Divide each number by the smaller number of moles

Co:O = 0.429 26:0.739 38 = 1:1.4999

Step 4. Multiply each number by a factor that makes the ratio close to whole numbers

Multiply by 2. Then

Co:O = 2:2.998 ≈ 2:3

Step 5: Write the empirical formula

EF = Co₂O₃

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3 years ago

What is true about energy?

xeze [42]

The correct answer is option A. Energy cannot be created during an ordinary chemical reaction. There is no such thing as an ordinary chemical reaction. Energy cannot be created or destroyed this is according to the law of conservation of energy. It can only be transformed from one form to another form.

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3 years ago

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0.500 mile of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (

SCORPION-xisa [38]

The correct question is as follows: 0.500 moles of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (plz help!)

Answer: The molarity of this solution is 0.25 M.

Explanation:

Molarity is the number of moles of a substance divided by volume in liter.

As it is given that there are 0.5 moles of potassium oxide in 2.00 L of water so, the molarity of this solution is calculated as follows.

$Molarity = \frac{moles}{volume(in L)}\\= \frac{0.5 moles}{2.00 L}\\= 0.25 M$

Thus, we can conclude that molarity of this solution is 0.25 M.

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2 years ago

The smell of fresh cut pine is due in part to the cyclic alkene called pinene. Given the following data of pinene: Vapor pressur

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Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

$ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = initial pressure at 429 K = 760 torr

$P_2$ = final pressure at 415 K = 515 torr

= enthalpy of vaporisation = ?

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 429 K

$T_2$ = final temperature = 515 K

Now put all the given values in this formula, we get

$\log (\frac{515}{760}=\frac{\Delta H}{2.303\times 8.314J/mole.K}[\frac{1}{429K}-\frac{1}{415K}]$

$\Delta H=41094J$

Thus the heat of vaporization is 41094 Joules

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3 years ago

Julia did an experiment to study the solubility of two substances. She poured 100 mL of water at 20 °C into each of two beakers

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Answer: The solubility of B is high than the solubility of A.

Explanation:

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For the given observations:

Mass of undissolved substance of substance A is more than Substance B at every temperature. This implies that less amount of solute gets dissolved in the given amount of solvent.

Hence, substance B has high solubility than substance A.

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