There are zero lone pairs of electrons on the central carbon atom in a Lewis Structure of CHI3. The correct option is b.
Explanation:
Lone pair electrons are those valence electrons of an atom which do not take part in bonding or left after the bonds are formed.
CH
carbon is the central atom in the compound having 4 valence electrons.
Each iodine molecule has 7 valence electrons.
H has 1 valence electron.
from the Lewis structure of CH, it is seen that all four valence electrons of the carbon is involved in bonding with 3 atoms of iodine and 1 atom of hydrogen.
Thus when all valence electrons are involved in bonding no lone pair of electron is found in CH that means zero lone pairs of electrons.
The octet of the iodine, carbon and hydrogen gets completed to form the compound.
I believe the answer is Zinc because it has 30protona
The substances largely ionic are:
NF3
N2
BrF3
PCl3
Answer:
Electrostatic Van de Waals forces act between molecules to form weak bonds. The types of Van der Waals forces, strongest to weakest, are dipole-dipole forces, dipole-induced dipole forces and the London dispersion forces. The hydrogen bond is based on a type of dipole-dipole force that is especially powerful. These forces help determine the physical characteristics of materials.
For N2(g)+3h2(g) ←→ 2nh3(g) The equilibrium system described by this equation has= 3 reactant molecule(s) and= 2 product gas molecule(s).
