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german
3 years ago
9

Help plz:)))I’ll mark u Brainliest

Chemistry
1 answer:
Wittaler [7]3 years ago
5 0

Answer:

2.475 mol of O2  formed.

Explanation:

Given 1.65 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of moles of O2 molecules formed.

x mole of  O2   = 1.65 mol  KClO3 x [(3 mol O2)/ (2 mol KClO3)] = 2.475 mol of O2

x mole of  O2 formed  = 2.475 mol of O2

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Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:
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<h3>What is the molecular shape of a compound?</h3>

The molecular geometry of the compound shows the position of nuclei and the electron of the compound. It shows how the joining of electrons and nuclei makes the shape of the compound.

Like here, the shape of nitrite is bent with lone pair which is shown by Lewis's structure The bond angle will be the distance between the nuclei of the neighbor atoms.

Thus, the electron geometry arrangement of nitrite is trigonal planer with a bent shape and the bond angle will be 120°.

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2 years ago
Which equation represents positron decay?
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Answer: 4

Explanation:

4 is the only one that has to products as well as having the plus at the bottom

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3 years ago
In Part A, we saw that the theoretical yield of aluminum oxide is 1.60 mol . Calculate the percent yield if the actual yield of
garri49 [273]

Taking into account definition of percent yield, the percent yield for the reaction is 76.25%.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield=\frac{actual yield}{theorical yield}x100

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Percent yield in this case</h3>

In this case, you know:

  • actual yield= 1.22 mol
  • theorical yield= 1.60 mol

Replacing in the definition of percent yields:

percent yield=\frac{1.22 mol}{1.60 mol}x100

Solving:

<u><em>percent yield= 76.25%</em></u>

Finally, the percent yield for the reaction is 76.25%.

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4 0
2 years ago
A. what is the e value for the oxidation of cytochrome c by the cua redox center in complex iv when the ratio of cyt c (fe3 ) /c
mariarad [96]

0.116 V is the e value for the oxidation of cytochrome c by the cue redox center in complex iv when the ratio of cyst c (fe3 ) /cyst c (fe2 ) is 20 and the ratio of cue (cu2 )/cue (cu ) is 3.

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When cytochrome c is oxidized by mitochondrial cytochrome oxidase (COX), it attaches to Apaf-1 to produce the apoptozole, which activates pro-caspase-9 and causes cell death. Cyst can be created from cytosolic cytochrome c. In the IMS, oxidized cytochrome c can scavenge superoxide without converting it into H2O2, a process that happens naturally but is accelerated by SOD. The benefit of scavenging superoxide independently of H2O2 synthesis is reducing the possibility of hydroxyl radical generation via the Fenton reaction.

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8 0
1 year ago
How many liters of carbon dioxide gas are there in 4 moles of CO2 at STP?
Ad libitum [116K]

Answer:

<u>89.6 L</u>

Explanation:

In normal conditions,

<u><em>For every </em></u><u><em>1 mole</em></u><u><em> of carbon dioxide at STP, it occupies </em></u><u><em>22.4 L</em></u><u><em> of volume.</em></u>

<u><em /></u>

============================================================

Solving :

⇒ 1 mole : 22.4 L

⇒ 1 × 4 : 22.4 × 4

⇒ 4 moles : <u>89.6 L</u>

4 0
2 years ago
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