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german
2 years ago
9

Help plz:)))I’ll mark u Brainliest

Chemistry
1 answer:
Wittaler [7]2 years ago
5 0

Answer:

2.475 mol of O2  formed.

Explanation:

Given 1.65 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of moles of O2 molecules formed.

x mole of  O2   = 1.65 mol  KClO3 x [(3 mol O2)/ (2 mol KClO3)] = 2.475 mol of O2

x mole of  O2 formed  = 2.475 mol of O2

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HELP ASAP !!!!!!Can someone tell me easy one line definitions of atomic number, mass number, and isotopes
rusak2 [61]

Answer:

Fundamental properties of atoms including atomic number and atomic mass. The atomic number is the number of protons in an atom, and isotopes have the same atomic number but differ in the number of neutrons.

Explanation:

Fundamental properties of atoms including atomic number and atomic mass. The atomic number is the number of protons in an atom, and isotopes have the same atomic number but differ in the number of neutrons.

5 0
3 years ago
how often should gas appliances be checked for proper operation in order to prevent carbon monoxide poisoning?
yawa3891 [41]
You should be checking your gas appliances every year, it should always be a qualified technician.
8 0
3 years ago
How many atoms are there in 3.559*10^-6 mol of krypton?
algol [13]

Answer:

The answer is

<h2>2.143 \times  {10}^{18}  \:  \: atoms</h2>

Explanation:

To find the number of atoms given the number of moles we use the formula

N = n × L

where

N is the number of entities

n is the number of moles

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 3.559 \times  {10}^{ - 6}  \: mol

Substitute the values into the above formula and solve

That's

<h3>N  = 3.559 \times  {10}^{ - 6}  \times 6.02 \times  {10}^{23}  \\  = 2.1425 \times  {10}^{18}</h3>

We have the final answer as

<h3>N  = 2.143 \times  {10}^{18}  \:  \: atoms</h3>

Hope this helps you

3 0
3 years ago
Which of the following equations are correctly balanced
IRINA_888 [86]
Ion know yo but good luck
7 0
3 years ago
If a chemist has a stock solution of HBr that is 10.0 M and would like to make 450.0 mL of 3.0 M HBr, how would he do it?
asambeis [7]

This is a dilution that requires a certain volume from the stock solution to be diluted with distilled water to make a solution of HBr with a lesser concentration than the stock solution

Following dilution formula can be used

c1v1 = c2v2

Where c1 is concentration and v1 is the volume of the stock solution

c2 is concentration and v2 is volume of the diluted solution to be prepared

Substituting these values

10.0 M x v1 = 3.0 x 450.0 mL

v1 = 135.0 mL

A volume of 135.0 mL from HBr stock solution needs to be taken and diluted with distilled water upto 450.0 mL. The resulting solution will have a concentration of 3.0 M

4 0
3 years ago
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