Answer:
Explanation:
pH = - log[H⁺]
8 = - log[H⁺]
[H⁺] = 10⁻⁸
if this concentration of hydrogen ion increases to 100 times
New hydrogen ion concentration
[H⁺] = 10⁻⁸ x 10²
= 10⁻⁶
pH = - log[10⁻⁶]
= 6
new pH will be 6 .
No. of moles= mass given /mass acquired
.0079=x/238
238×.0079=x
1.88~2
therefore the no. of grams =2g
First, lets find the pOH
pOH=-log[OH] ----> pOH=-log[1x10^-12] ----->pOH=12
Now we can find the pH
14-12=2
Now we can use the pH=-log[H3O] to find the hydrogen ion concentration
2=-log[H3O] ------>[H3O]=1.0 x 10^-2