we know that
if the exponential function passes through the given point, then the point must satisfy the equation of the exponential function
we proceed to verify each case if the point
satisfied the exponential function
<u>case A</u> ![f(x)=4(x^{5})](https://tex.z-dn.net/?f=f%28x%29%3D4%28x%5E%7B5%7D%29)
For
calculate the value of y in the equation and then compare with the y-coordinate of the point
so
![f(2)=4(2^{5})=128](https://tex.z-dn.net/?f=f%282%29%3D4%282%5E%7B5%7D%29%3D128)
![128\neq 80](https://tex.z-dn.net/?f=128%5Cneq%2080)
therefore
the exponential function
not passes through the point ![(2,80)](https://tex.z-dn.net/?f=%282%2C80%29)
<u>case B</u> ![f(x)=5(x^{4})](https://tex.z-dn.net/?f=f%28x%29%3D5%28x%5E%7B4%7D%29)
For
calculate the value of y in the equation and then compare with the y-coordinate of the point
so
![f(2)=5(2^{4})=80](https://tex.z-dn.net/?f=f%282%29%3D5%282%5E%7B4%7D%29%3D80)
![80=80](https://tex.z-dn.net/?f=80%3D80)
therefore
the exponential function
passes through the point ![(2,80)](https://tex.z-dn.net/?f=%282%2C80%29)
<u>case C</u> ![f(x)=4(5^{x})](https://tex.z-dn.net/?f=f%28x%29%3D4%285%5E%7Bx%7D%29)
For
calculate the value of y in the equation and then compare with the y-coordinate of the point
so
![f(2)=4(5^{2})=100](https://tex.z-dn.net/?f=f%282%29%3D4%285%5E%7B2%7D%29%3D100)
![100\neq 80](https://tex.z-dn.net/?f=100%5Cneq%2080)
therefore
the exponential function
not passes through the point ![(2,80)](https://tex.z-dn.net/?f=%282%2C80%29)
<u>case D</u> ![f(x)=5(4^{x})](https://tex.z-dn.net/?f=f%28x%29%3D5%284%5E%7Bx%7D%29)
For
calculate the value of y in the equation and then compare with the y-coordinate of the point
so
![f(2)=5(4^{2})=80](https://tex.z-dn.net/?f=f%282%29%3D5%284%5E%7B2%7D%29%3D80)
![80=80](https://tex.z-dn.net/?f=80%3D80)
therefore
the exponential function
passes through the point ![(2,80)](https://tex.z-dn.net/?f=%282%2C80%29)
therefore
<u>the answer is</u>
![f(x)=5(x^{4})](https://tex.z-dn.net/?f=f%28x%29%3D5%28x%5E%7B4%7D%29)
![f(x)=5(4^{x})](https://tex.z-dn.net/?f=f%28x%29%3D5%284%5E%7Bx%7D%29)
Answer:
3 plus -5 means you go backwards from +3 to -2 thats your answer
Step-by-step explanation:
The concentration of ions in the solution of lemon juice whose pH value is 2.32 is 4.79×10⁻³ M.
<h3>What is pH value?</h3>
The pH value shows that how much a solution is acidic or basic. The range of the pH value lies between the 0-14.
The pH value can be calculated with the following formula.
![\rm pH=log[H^{+}]](https://tex.z-dn.net/?f=%5Crm%20pH%3Dlog%5BH%5E%7B%2B%7D%5D)
Here, [H⁺] is the molar hydrogen ion concentration.
The pH of lemon juice at 298 K is found to be 2. 32. Put this value of pH in the above formula as,
![\rm 2.32=log[H^{+}]\\\ [H^{+}]=4.79\times10^{-3} \rm \; M](https://tex.z-dn.net/?f=%5Crm%202.32%3Dlog%5BH%5E%7B%2B%7D%5D%5C%5C%5C%20%5BH%5E%7B%2B%7D%5D%3D4.79%5Ctimes10%5E%7B-3%7D%20%5Crm%20%5C%3B%20M)
Hence, the concentration of ions in the solution of lemon juice whose pH value is 2.32 is 4.79×10⁻³ M.
Learn more about the pH value here;
brainly.com/question/940314
Answer:
In Mathematics Geometry,<em> lateral face</em> is said be the side of a 3D-figure in that is not a base.
Please check the attached figure to visual the concept.
Step-by-step explanation:
In Mathematics Geometry,<em> lateral face</em> is said be the side of a 3D-figure in that is not a base.
The faces in in a prism or pyramid which are not bases are basically the lateral faces.
For example, the lateral faces are basically parallelograms in Triangular prism which are not the bases.
Please check the attached figure to visual the concept.