Answer:
MMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMM
Step-by-step explanation:
MMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMM
Answer:
a) 1133.98 ≈ 1134 packs
b) 125 packs
Step-by-step explanation:
Given:
Tar present in 1 cigarette = 5 mg
Nicotine present in 1 cigarette = 0.4 mg
Number of cigarettes in 1 pack = 20
thus,
Tar present in 1 pack of cigarette = 5 × 20 = 100 mg
Nicotine present in 1 pack of cigarette = 0.4 × 20 = 8 mg
now,
1 oz = 28349.5 mg
thus,
for 4 oz = 4 × 28349.5 mg = 113398 mg
Therefore,
Number of packs required for 4 oz ( 113398 mg ) tar
= 
= 1133.98 packs ≈ 1134
also,
Number of packs required for 1 g (1000 mg) nicotine
= 
= 125 packs
Answer:
ONES Period
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
14 - (17 - 5) + 8
PEMDAS says parentheses first
14 - (12) + 8
Since we have no exponents, or multiplication or division
We add and subtract from left to right.
2+8
10
Answer:
3f(x)
Step-by-step explanation:
I mean there's three added together so its 3 times f(x)
