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Yakvenalex [24]
3 years ago
14

Please Help! Geometry!

Mathematics
1 answer:
UkoKoshka [18]3 years ago
3 0

Step-by-step explanation:

arcLM = 2\pi .r (\frac{72}{360} )

= 2\pi(1) \times 0.2

= 0.4\pi

You might be interested in
The equations that must be solved for maximum or minimum values of a differentiable function w=​f(x,y,z) subject to two constrai
sammy [17]

The Lagrangian is

L(x,y,z,\lambda,\mu)=x^2+y^2+z^2+\lambda(4x^2+4y^2-z^2)+\mu(2x+4z-2)

with partial derivatives (set equal to 0)

L_x=2x+8\lambda x+2\mu=0\implies x(1+4\lambda)+\mu=0

L_y=2y+8\lambda y=0\implies y(1+4\lambda)=0

L_z=2z-2\lambda z+4\mu=0\implies z(1-\lambda)+2\mu=0

L_\lambda=4x^2+4y^2-z^2=0

L_\mu=2x+4z-2=0\implies x+2z=1

Case 1: If y=0, then

4x^2-z^2=0\implies4x^2=z^2\implies2|x|=|z|

Then

x+2z=1\implies x=1-2z\implies2|1-2z|=|z|\implies z=\dfrac25\text{ or }z=\dfrac23

\implies x=\dfrac15\text{ or }x=-\dfrac13

So we have two critical points, \left(\dfrac15,0,\dfrac25\right) and \left(-\dfrac13,0,\dfrac23\right)

Case 2: If \lambda=-\dfrac14, then in the first equation we get

x(1+4\lambda)+\mu=\mu=0

and from the third equation,

z(1-\lambda)+2\mu=\dfrac54z=0\implies z=0

Then

x+2z=1\implies x=1

4x^2+4y^2-z^2=0\implies1+y^2=0

but there are no real solutions for y, so this case yields no additional critical points.

So at the two critical points we've found, we get extreme values of

f\left(\dfrac15,0,\dfrac25\right)=\dfrac15 (min)

and

f\left(-\dfrac13,0,\dfrac23\right)=\dfrac59 (max)

5 0
4 years ago
Help asp
Svetradugi [14.3K]
<h3>The temperature drop from the morning to the night is -16.8 F</h3>

<em><u>Solution:</u></em>

Given that,

The temperature in the morning was -4 F

At night the temperature dropped to -12.8 F

To find: temperature drop from the morning to the night be represented

From given,

Morning = -4 F

Night = -12.8 F

Therefore,

Temperature drop from the morning to the night = -4 - 12.8 = -16.8 F

Thus the temperature drop from the morning to the night is -16.8 F

3 0
3 years ago
What is the inverse of the function f(x) = 2x – 10?
strojnjashka [21]

Answer:

see explanation

Step-by-step explanation:

let y = f(x) then rearrange making x the subject

y = 2x - 10 ( add 10 to both sides )

y + 10 = 2x ( divide both sides by 2 )

\frac{y+10}{2} = x

Change y back into terms of x

f^{-1} (x) = \frac{x+10}{2}

6 0
3 years ago
£980 is divided between Caroline, Sarah &amp; Gavyn so that Caroline gets twice as much as Sarah, and Sarah gets three times as
Nitella [24]

Sarah has received £ 294

<u><em>Solution:</em></u>

Given that £980 is divided between Caroline, Sarah & Gavyn

Let "c" be the amount received by caroline

Let "s" be the amount received by sarah

Let "g" be the amount received by gavyn

<em><u>Caroline gets twice as much as Sarah</u></em>

amount received by caroline = twice as much as Sarah

amount received by caroline = 2(amount received by sarah)

c = 2s ---- eqn 1

<em><u>Sarah gets three times as much as Gavyn</u></em>

amount received by sarah = three times as much as Gavyn

amount received by sarah = 3(amount received by gavyn)

s = 3g ------- eqn 2

Given that total amount is 980

c + s + g = 980 --- eqn 3

<em><u>Let us solve eqn 1, 2, 3 to get values of "c" "s" "g"</u></em>

From eqn 2,

g = \frac{s}{3}  --- eqn 4

Substitute eqn 1 and eqn 4 in eqn 3

2s + s + \frac{s}{3} = 980\\\\\frac{6s + 3s + s}{3} = 980\\\\6s + 3s + s = 980 \times 3\\\\10s = 2940\\\\s = 294

Thus sarah has received £ 294

7 0
3 years ago
(3k^3+4k^2-2)-(5k^2-9)-(7k^3+6k)
mr Goodwill [35]

Answer:

− 4 k3− k 2− 6 k+7

Step-by-step explanation:

I just simplified the expression.

4 0
3 years ago
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