Answer:
Explanation:
<u>Given Data:</u>
Volume = v = 1.12 dm³ = 1.12 L
Density of nitrogen at STP = D = 1.25 g / L
Molar mass = M = 14 * 2 = 28 g / mol
Avogadro's Number = 
= 6.023 * 10²³ mol⁻¹
<u>Required:</u>
No. of molecules = ?
<u>Formula:</u>
<u>Solution:</u>
No. of molecules = (1.25*1.12) / 28 * (6.023 * 10²³)
No. of molecules = ( 1.4 / 28 ) * 6.023 * 10²³
No. of molecules = 0.05 * 6.023 * 10²³
No. of molecules = 0.3 * 10²³
No. of molecules = 3 * 10²² molecules
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
Your question is not complete, but use this answer as a guide for your solution.
Question: A chemistry student weighs out 0.112g of acetic acid (HCH₃CO₂) into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1600 <em>M</em> NaOH solution. Calculate the volume of solution the student will need to add to reach the equivalence point. Be sure your answer has the correct number of significant digits.
Answer: Volume of NaOH is 11.6 mL
Explanation:
The reaction of acetic acid with NaOH is as follows:
CH3COOH + NaOH -----> CH3COONa + H2O
M1V1 = M2V2
Here M1 V1 are molarity and volume of acetic acid.
M2, V2 are molarity and volume of NaOH.
Number of moles of acetic acid:
0.112 g CH3COOH × (1 mol / 60.05 g) = 0.001865 mol
Molarity = moles of solute / Liters of solution
Molarity = 0.001865 mol / 0.250 L = 0.00746 M
Hence,
M1 = 0.00746 M
V1 = 250 mL
M2 = 0.160 M
V2 = ?
V2 = M1V1 / M2
V2 = 0.00746 M × 250 mL / 0.160 M
V2 = 11.6 mL
Hence the volume of NaOH is 11.6 mL
Explanation:
I think it is maintaining certain internal condition
Heat is released.
When a chemical change occurs, energy comes out of the atoms which causes heat.
