The delta H of -484 kJ is the heat given off when 2 moles of H2 react with 1 mole of O2 to make 2 moles of H2O. You don't have anywhere near that much reactants, only 1/4 as much
<span>actual delta H = 0.34 moles H2 x (-484 kJ / 2 moles H2) = 823 kJ </span>
<span>delta E = delta H - PdeltaV = 823 kJ - 0.41 kJ = 822 kJ</span>
Answer:
Explanation: in exothermic reaction heat is released out
In endothermic reaction heat is absorbed
The answer is 1/8.
Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1.

,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample
2.

where:
<span>

- half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
<span>

= 28.8 years
We need:
n = ?
x = ?
</span>
We could first use the second equation, to calculate n:
<span>If:

,
</span>Then:

⇒

⇒

<span>⇒ n ≈ 3
</span>
Now we can use the first equation to calculate the remained amount of the sample.
<span>

</span>⇒

⇒

<span>
</span>
The answer:
La planta tiene las hojas secas.
Answer:
Option e and f are possible
Explanation:
Since we know that 0.264 gallon = 1L ⇒ we change this in all equations.
8.08 L * A =
a) 8.08 L * 0.264 gal / 8.08 L = 0.264 gal = 1L
b) 8.08 L * 8.08 gallon / 0.264L = (8,08/ 0.264) L/0.264 L = 30.61 / 0.264 = 115.93 L *8.08 L
c) 8.08 L * 8.08 gallon / 1L = (8,08/ 0.264) L/1 L = 30.61 L * 8.08 L
d) 8.08 L * 0.264 L / 1 gallon =8.08 L * 0.264 L / 1 gal
e) 8.08 L * 0.264 gallon / 1L = 8.08 L *1L / 1L = 8.08 L
f) 8.08 L * 1L / 0.264 gallon = 8.08L * 1L / 1L = 8.08 L
The last 2 options are possible ( e and f )