Five valence electrons for one nitrogen and 10 valence electrons for two nitrogens
Answer: It is false because we use alot of it to with solar power.
Answer: mass m = M·c·V
Explanation: M(CaCl2) = 110.98 g/mol, c= 0.15 mol/l,
n=m/M= cV, volume of Solution is not mentioned
Answer:
29.42 Litres
Explanation:
The general/ideal gas equation is used to solve this question as follows:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K
According to the information provided in this question;
mass of nitrogen gas (N2) = 25g
Pressure = 0.785 atm
Temperature = 315K
Volume = ?
To calculate the number of moles (n) of N2, we use:
mole = mass/molar mass
Molar mass of N2 = 14(2) = 28g/mol
mole = 25/28
mole = 0.893mol
Using PV = nRT
V = nRT/P
V = (0.893 × 0.0821 × 315) ÷ 0.785
V = 23.09 ÷ 0.785
V = 29.42 Litres
Answer:
There are 12 nanoseconds in
.
Explanation:
We need to convert
to nanoseconds.
We know that,

Now using unitary method to solve it such that,

So, there are 12 nanoseconds in
.